In: Chemistry
Using the Bohr Model of the atom, consider an electron starting in the n=5 state of a hydrogen atom that emits a photon in the UV range as it drops to lower energy.
A) Determine the final state, nf, after the atom emits the photon.
B)Calculate the change in energy of the electron.
C)Calculate the frequency of the photon emitted.
D) Calculate the wavelenght of the photon in nm. Need some help! Thank you in advanced!
When an electron jump from n= 5 to n= 1 lymann sries in UV region.
A. nf = 1
B. En = -2.172*10^-18/n^2
n = 5
E5 = -2.172*10^-18/(5)^2 = -8.688*10^-20 J
n = 1
E1 = -2.172*10^-18/(1)^2 = -2.172*10^-18 J
DE = E5-E1 = -8.688*10^-20-(-2.172*10^-18 ) = -0.08688*10^--18 - (-2.172*10^-18)
=2.08512*10^-18J
C. DE = hv
v = DE/h
= 2.08512*10^-18/6.625*10^-34 = 3.15*10^15 htz
D. DE = hC/lamda
lamda = hc/DE
= 6.625*10^-34*3*10^8/2.08512*10^-18 = 9.53*10^-8m = 95.3nm