Question

In: Physics

a) Find the energy of an electron in the n=5 state of the hydrogen atom.

b) Find the energy of an electron in the n=6 state of the hydrogen atom.

c) If an electron initially in the n= 6 state falls to the n= 5 state, how much energy must the electron give up?

d) If an electron initially in the n= 6 state falls to the n=5 state, what is the wavelength of the photon that will be emitted?

Solutions

Expert Solution

Energy of electron in in hydrogen atom is given by:

Where, n is no of orbit/state in which electron is present.

Z is the atomic number , for hydrogen atom Z=1

a). Now energy of electron in n= 5 state is

b).Now energy of electron in n=6 orbit /state is:

c). As we have shown n=6 has higher energy (less negative value ) than n=5 so when electron jumps from n=6 to n=5 energy will release in form of photons

Energy released = difference in energy of n=6. and n=5 orbit/state .

d).Energy of photon

Where h : planck's constant

c: speed of light in vacuum

: wavelength of emitted light

Now

Wavelength of emitted photon is

genius_generous answered 1 year ago

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