Question

A 1.5 kg block of iron at 32 ∘C is rapidly heated by a torch such that 14 kJ is transferred to it. What temperature would the block of iron reach (assuming the complete transfer of heat and no loss to the surroundings)? If that same amount of heat (14 kJ ) was quickly transferred to a 890 g pellet of copper at 31 ∘C, what temperature would the copper reach before it begins losing heat to the surroundings? Use the equation for heat capacity and the following heat capacity values: qcs, Fe(s)cs, Cu(s)===mcsΔT0.450 J/(g⋅∘C)0.385 J/(g⋅∘C)

Answer 1

the equation for heat capacityq=maT

q amount of heat transffered=14kj=14000J

m is the mass of ironblock=1.5kg=1500gm

c is the specific heat capacity=0.450J/gm.0c

we can rearrange the equation asT=q/mc=14000J/(1500gm*0.450J/gm.0c)

                                                                 =20.740c

T=Tfinal-Tinitial

we need to determin T final=T+T intial

                                      =20.740c+320c=52.740c

b)T=q/mc

q is the amont of heat transfered=14000j

m mass of copper pellet=890gm

c the specific heat capacity of copper=0.385j/gm.0c

T=14000J/(890gm*0.385J/gm.0c)

      =40.860c

Tfinal=T+Tinitial

        =40.86+31=71.860c