Question

In: Chemistry

Does the ionic strength of saturated CaSO4 solution in de-ionized water have a significant impact on...

Does the ionic strength of saturated CaSO4 solution in de-ionized water have a significant impact on its solubility? What does this imply on an atomic scale about the interactions between Ca2+ and SO42- ions in the solution?

Solutions

Expert Solution

ionic strength is typically a measure of the concentration of ions in a solution ,,with the ions of higher charge being more counted as they impart more electrostatic attractions with ions of opposite charges.

I=Ionic strength=Ci*zi^2 ,Zi=charge of species i,ci=concentration of ionic species i

Also ,activity =ai=ci*i

i=mean ionic activity

Solubility of an electrolyte can be accounted for by using their solubility product or Ksp which is the measure of the product of activity of ions in solution

For any electrolyte,

AmBn <--->mAn+ +nBm-

Ksp=a(An+)^m* a(Bm-)^n

For CaSO4,Ksp=a(Ca2+) * a(SO42-)=(+)[Ca2+] * (-)[SO42-]

So, Ksp varies inversely as or mean ionic activity of ions,=+ *-

And, Ksp varies directly as Ci or concentration of ions

Thus,Ksp or solubility varies directly as Ionic strength.It increases with ionic strength.

On atomic scale ,it can be incurred that ions with higher solubility ,have more ions in solutions so the electrostatic interactions between ions is more,giving higher measure of ionic strength.


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