In: Statistics and Probability
Four different coatings are being considered for corrosion protection of metal pipe. The pipe will be buried in three different types of soil. To investigate whether the amount of corrosion depends either on the coating or on the type of soil, 12 pieces of pipe are selected. Each piece is coated with one of the four coatings and buried in one of the three types of soil for a fixed time, after which the amount of corrosion (depth of maximum pits, in 0.0001 in.) is determined. The data appears in the table.
Soil Type (B) | 1 | 2 | 3 |
Coating (A) 1| 65 | 46 | 52 |
2| 54 | 52 | 49 |
3| 49 | 45 | 51 |
4| 51 | 44 | 51 |
(a) Assuming the validity of the additive model, carry out the ANOVA analysis using an ANOVA table to see whether the amount of corrosion depends on either the type of coating used or the type of soil. State the appropriate hypotheses for the coating effect.
A) H0A: α1 ≠ α2 ≠ α3 ≠ α4 HaA: at least one αi = 0
B) H0A: α1 = α2 = α3 = α4 = 0 HaA: no αi = 0
C) H0A: α1 ≠ α2 ≠ α3 ≠ α4 HaA: all αi's = 0
D) H0A: α1 = α2 = α3 = α4 = 0 HaA: at least one αi ≠ 0
State the appropriate hypotheses for the soil type factor.
H0B: β1 ≠ β2 ≠ β3 HaB: all βj's are equal
H0B: β1 = β2 = β3 = 0 HaB: no βj = 0
H0B: β1 ≠ β2 ≠ β3 HaB: at least one βj = 0
H0B: β1 = β2 = β3 = 0 HaB: at least one βj ≠ 0
Complete the ANOVA table. Use α = 0.05. (Round your answers to two decimal places.)
Source : | df | SS | MS | f F0.05
A:|____| _____ | ______ | _____ |
B:|____| _____ | ______ | _____ |
Error:|____| ______| ______ | ______ |
Total: |____| _____ | _______ | _______ |
What can you conclude for H0A? Select a choice.
A) Reject H0A. The data does not suggest that there is a coating effect.
B) Fail to reject H0A. The data does not suggest that there is a coating effect.
C) Fail to reject H0A. The data suggests that there is a coating effect.
D) Reject H0A. The data suggests that there is a coating effect.
What can you conclude for H0B? Select a choice
Fail to reject H0B. The data suggests that there is a soil type effect.
Reject H0B. The data suggests that there is a soil type effect.
Reject H0B. The data does not suggest that there is a soil type effect.
Fail to reject H0B. The data does not suggest that there is a soil type effect.
(b) Compute the model parameters. (Round your answers to two decimal places.)
mu hat =
alpha hat1 =
alpha hat2 =
alpha hat3 =
alpha hat4 =
beta hat1 =
beta hat2 =
beta hat3 =
a)
D) H0A: α1 = α2 = α3 = α4 = 0 HaA: at least one αi ≠ 0
B) β1 = β2 = β3 = 0 HaB: at least one βj ≠ 0
using excel data analysis tool for one factor anova, following o/p Is obtained,
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Rows | 71.58 | 3 | 23.86 | 1.15 | 0.40 | 4.76 |
Columns | 128.00 | 2 | 64.00 | 3.08 | 0.12 | 5.14 |
Error | 124.67 | 6 | 20.78 | |||
Total | 324.25 | 11 |
p-value for coating effect = 0.40>α=0.05, so, fail to reject Ho, hence,
B) Fail to reject H0A. The data does not suggest that there is a coating effect
p-value for soil type=0.12>α,fail to reject Ho, hence,
Fail to reject H0B. The data does not suggest that there is a soil type effect.
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mu hat = Σx/n = 609/12=50.75
alpha gat = Xj bar - mu hat
alpha hat1 = 54.33 - 50.75 = 3.58
alpha hat2 =51.67-50.75=0.92
alpha hat3 =48.33-50.75 = -2.42
alpha hat4 =48.67 - 50.75 = -2.08
beta hat1 = 54.75-50.75= 4.00
beta hat2 =46.75-50.75= -4.00
beta hat3 =50.75-50.75 = -2.08