In: Statistics and Probability
Four brands of lightbulbs are being considered for use in the final assembly area of the Ford F-150 truck plant in Dearborn, Michigan. The director of purchasing asked for samples of 160 from each manufacturer. The numbers of acceptable and unacceptable bulbs from each manufacturer are shown below. At the 0.05 significance level, is there a difference in the quality of the bulbs?
Manufacturer A B C D Unacceptable 11 24 17 33 Acceptable 149 136 143 127 Total 160 160 160 160
H0: There is no relationship between quality and manufacturer.
H1: There is a relationship.
A) State the decision rule using 0.05 significance level. (Round your answer to 3 decimal places.)
Reject H0 if chi-square >
B)Compute the value of chi-square. (Round your answer to 3 decimal places.)
Chi-square value
C) What is your decision regarding H0?
__ H0. There is ____ evidence to conclude that a relationship exists between quality and manufacturer.
A | B | C | D | |
Unacceptable | 11 | 24 | 17 | 33 |
Acceptable | 149 | 136 | 143 | 127 |
Total | 160 | 160 | 160 | 160 |
This is a test of independence since we have to check whether the quality is independent of the manufacturer or not. We therefore use a chi-square test of independence.
A | B | C | D | Total | |
Unacceptable | 11 | 24 | 17 | 33 | 85 |
Acceptable | 149 | 136 | 143 | 127 | 555 |
Total | 160 | 160 | 160 | 160 | 640 |
The table for expected values is below
Eg: E(A|Acceptable) = =
E(A|unAcceptable) = =
E(A) | E(B) | E ( C) | E(D) | Total | |
Unaccepetable | 21.25 | 21.25 | 21.25 | 21.25 | 85 |
Acceptable | 138.75 | 138.75 | 138.75 | 138.75 | 555 |
Total | 160 | 160 | 160 | 160 | 640 |
Observed - expected
Eg: For A and unacceptable =
A | B | C | D | |
Unacceptable | 4.944118 | 0.355882 | 0.85 | 6.497059 |
Acceptable | 0.757207 | 0.054505 | 0.13018 | 0.995045 |
= 14.584
A) State the decision rule using 0.05 significance level. (Round your answer to 3 decimal places.)
Reject H0 if chi-square > Critical value
Where C.V. =
r (row) = 2 c(column) = 4 = 0.05
= 7.81
Reject H0 if chi-square > 7.81
B)Compute the value of chi-square. (Round your answer to 3 decimal places.)
Chi-square value =
Chi-square value = 14.584
C) What is your decision regarding H0?
Since
_Reject_ H0. There is sufficient evidence to conclude that a relationship exists between quality and manufacturer.