In: Chemistry
8H2S(g)+4O2(g)→8H2O(g)+S8(g) Δ[H2S]/Δt = -0.012 M/s
a)Find Δ[O2]/Δt.
b)Find Δ[H2O]/Δt.
c)Find Δ[S8]/Δt.
d)Find the rate of the reaction.
rate = decrease in concentration of reactant / time taken = increase in concentration of product / time taken.
a)
-1/8 [H2S] / t = -1/4 [O2] / t
[H2S] / t = - 0.012 M/s
[O2] / t = 4/8 [H2S] / t
[O2] / t = 4/8 (-0.012 )
[O2] / t = - 0.006 M/s
b)
-1/8 [H2S] / t = 1/8 [H2O]/t
- [H2S] / t = [H2O]/t
[H2O]/t = - (0.012)
[H2O]/t = 0.012 M/s
c)
1/8 [H2O]/t = [S8] / t
[S8] / t = 1/8 (0.012)
[S8] / t = 0.0015 M/s
d)
rate = [S8] / t
rate = 0.0015 M/s