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A proton moves through a uniform magnetic field given by  B→=(5.52i^−10.0j^+20.9k^) mT. At time t1, the proton...

A proton moves through a uniform magnetic field given by  B→=(5.52i^−10.0j^+20.9k^) mT. At time t1, the proton has a velocity given by   v→=vxi^+vyj^+(2.19⁢  km/s)k^ and the magnetic force on the proton is   F→B=(3.69×10−17⁢ N)i^+(2.03×10−17⁢ N)j^ . (a) At that instant, what is vx? (b) At that instant, what is vy?

(a) _ m/s

(b) _ m/s

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genius_generous answered 9 months ago
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