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A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.50 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1830 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.10 V/m, (b) in the negative z direction and has a magnitude of 5.10 V/m, and (c) in the positive x direction and has a magnitude of 5.10 V/m?

Solutions

Expert Solution

The net force on a charged particle moving in presence of both magnetic field and the electric field is given by Lorentz Force.

Given and known data:

Part (a):

The net force acting on the proton is:

The magnitude of the net force acting on the proton is:

Part (b):

The net force acting on the proton is:

The magnitude of the net force acting on the proton is:

Part (c):

The net force acting on the proton is:

The magnitude of the net force acting on the proton is: ​​​​​​​​​​​​​​

genius_generous answered 9 months ago
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