Question

In: Statistics and Probability

A Pre-School teacher has created a new curriculum for teaching students new words. The new curriculum...

A Pre-School teacher has created a new curriculum for teaching students new words. The new curriculum is denoted as curriculum A and the original curriculum is denoted as curriculum B. The teacher instructs one class under curriculum A and a separate class under curriculum B. The number of new words each student learns is recorded and the teacher constructs a confidence interval for: ua-ub. The 95% t-confidence interval obtained is (1.26, 4.78).

(i) Based on the confidence interval the teacher constructed, do students learn the same number of words on average under curriculums A and B? Explain how you reached your conclusion. (ii) Interpret the confidence interval in words.

(iii) What requirements are needed for the above confidence interval to be valid?

Solutions

Expert Solution

(i) The 95% confidence interval is (1.26, 4.78) for ua-ub. Since 0 does not lie in this confidence interval, we can conclude that the students learn more numbers of words on an average under curriculum A then they do under curriculum B. In other words students do not learn the same number of words on average under curriculum A and B. Since 0 does not lie in the given confidence interval we can say with 95% certainty that ua>ub

(ii) We can be 95% confident that the true mean difference between the average number of words learned under curriculum A and the average number of words learned under curriculum B lies between 1.26 and 4.78

(iii)

The following conditions must have been met:

  • Randomization: The sample students must be selected randomly from the both the classes.
  • Independent : The sample students number of words learnt must be independent of other students number of words learnt and must only be based on the teachers teachings of the curriculum.

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