Question

In: Chemistry

Analyze how how efficiency can be just a function of the two temperatures for Carnot Cycle...

Analyze how how efficiency can be just a function of the two temperatures for Carnot Cycle of ideal gas.

Solutions

Expert Solution


Related Solutions

Analyze Carnot Cycle for ideal gases
Analyze Carnot Cycle for ideal gases
Efficiency of an engine operating condition to Carnot cycle is equal to ? = 0.45. Temperature...
Efficiency of an engine operating condition to Carnot cycle is equal to ? = 0.45. Temperature and specific volume of the gaseous working medium at the beginning of isentropic compression are T1 = 600 K and v1 = 0.5 m3/Kg respectively. Find the gas properties at all other characteristic points of the cycle and the amount of heat released during isothermal compression. Assume that the mass of 1Kg of the gas undergoes the sequence of processes corresponding to Carnot cycle....
Q2. Two kilograms of air within a piston-cylinder configuration execute a Carnot power cycle between temperatures...
Q2. Two kilograms of air within a piston-cylinder configuration execute a Carnot power cycle between temperatures 750 K and 300 K. The isothermal expansion is associated with a heat input of 60 kJ from the surroundings. The volume after expansion has occurred isothermally is 0.4 m3 . Assuming air behaves as an ideal gas, calculate: (i) thermal efficiency for the cycle (ii) pressure and volume at the beginning of the isothermal expansion, in kPa and m3 , respectively. (iii) the...
Q2. Two kilograms of air within a piston-cylinder configuration execute a Carnot power cycle between temperatures...
Q2. Two kilograms of air within a piston-cylinder configuration execute a Carnot power cycle between temperatures 750 K and 300 K. The isothermal expansion is associated with a release of 60 kJ of heat into the surroundings. The volume after expansion has occurred isothermally is 0.4 m3 . Assuming air behaves as an ideal gas, calculate: (i) thermal efficiency for the cycle (ii) pressure and volume at the beginning of the isothermal expansion, in kPa and m3 , respectively. (iii)...
Derive the efficiency of a Carnot cycle any way you like. Diagram will be appreciated
Derive the efficiency of a Carnot cycle any way you like. Diagram will be appreciated
A Carnot engine operates between temperatures of 200 K and 350 K. In each cycle, 4000...
A Carnot engine operates between temperatures of 200 K and 350 K. In each cycle, 4000 J of heat is added to the ideal gas. This engine works on 0.5 mols of a diatomic gas. A) Calculate the volume ratio for just the adiabatic expansion. B) Determine the compression ratio - the highest volume divided by the lowest. C) If you reversed the cycle, how much work would be necessary to pull 100 J of heat from the cold temperature...
Devise a Carnot Heat Pump using steady flow components and describe how the Carnot cycle is...
Devise a Carnot Heat Pump using steady flow components and describe how the Carnot cycle is executed in that device. Elaborately explain.
Air within a piston-cylinder assembly execute an ideal Carnot power cycle within maximum and minimum temperatures...
Air within a piston-cylinder assembly execute an ideal Carnot power cycle within maximum and minimum temperatures of 600 K and 300 k, respectively. The heat added at the high temperature is 250 kJ/kg. The lowest pressure in the cycle is 75 kPa. Assuming the ideal gas model for the air (constant cv, cp, k, with the following properties: kair = 1.4, cv,air = 0.717 J/g.K, Mair = 28.97 g/mol, Universal Gas Constant 8.314 /( . ) _ R = J...
how can the second law efficiency of a simple ideal rankine cycle can be improved
how can the second law efficiency of a simple ideal rankine cycle can be improved
Can someone please explain the Carnot Cycle graph in terms of what equations to use and...
Can someone please explain the Carnot Cycle graph in terms of what equations to use and the concepts. This is what I think but I keep getting mixed up: Path A to B which is Reversible Isothermal Expansion, Delta U= 0, and according to first law Q= -W and we use RTln V2/V1 for W?  In path B to C, the gas expand Adiabatically, so Q= 0 and Delta U= - W. Since it is expansion so the work will be...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT