Question

In: Statistics and Probability

Suppose the preliteracy scores of three-year-old students in the United States are normally distributed. Shelia, a...

Suppose the preliteracy scores of three-year-old students in the United States are normally distributed. Shelia, a preschool teacher, wants to estimate the mean score on preliteracy tests for the population of three-year-olds. She draws a simple random sample of 20 students from her class of three-year-olds and records their preliteracy scores (in points).

80,81,89,90,91,91,91,94,95,95,95,101,101,102,102,104,104,108,109,11180,81,89,90,91,91,91,94,95,95,95,101,101,102,102,104,104,108,109,111

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Calculate the sample mean (?⎯⎯⎯x¯), sample standard deviation (?s), and standard error (SE) of the students' scores. Round your answers to four decimal places.

Determine the ?t-critical value (?t) and margin of error (?m) for a 90% confidence interval. Round your answers to three decimal places.

What are the lower and upper limits of a 90% confidence interval? Round your answers to three decimal places.

?⎯⎯⎯=x¯=

?=s=

?t =

SE=SE=

?m =

lower limit:

upper limit:

Which is the correct interpretation of the confidence interval?

There is a 90% chance that the population mean is between 93.350 points and 100.050 points.

Shelia is 90% confident that the true population mean is between 93.350 points and 100.050 points.

Shelia is 90% confident that the true population mean is between 95.513 points and 99.887 points.

Shelia is certain that the true population mean is between 93.350 points and 100.050 points.

There is a 90% chance that the true population mean is between 95.513 points and 99.887 points.

Solutions

Expert Solution

Solution:

Sample size = n = 20

Part a) Calculate the sample mean , sample standard deviation ( s), and standard error (SE)

Formula:

Thus we need to make following table:

x x^2
80 6400
81 6561
89 7921
90 8100
91 8281
91 8281
91 8281
94 8836
95 9025
95 9025
95 9025
101 10201
101 10201
102 10404
102 10404
104 10816
104 10816
108 11664
109 11881
111 12321

Thus

and

Part b) Determine the t-critical value (t) and margin of error ( m) for a 90% confidence interval.

df   = n - 1 = 20 - 1 = 19

Two tail area = 1 - 0.90 = 0.10

t critical value = 1.729

Margin of Error is:

Part c) What are the lower and upper limits of a 90% confidence interval?

and

Part d) Which is the correct interpretation of the confidence interval?

Shelia is 90% confident that the true population mean is between 93.350 points and 100.050 points.


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