In: Statistics and Probability
Suppose the preliteracy scores of three-year-old students in the United States are normally distributed. Shelia, a preschool teacher, wants to estimate the mean score on preliteracy tests for the population of three-year-olds. She draws a simple random sample of 20 students from her class of three-year-olds and records their preliteracy scores (in points).
80,81,89,90,91,91,91,94,95,95,95,101,101,102,102,104,104,108,109,11180,81,89,90,91,91,91,94,95,95,95,101,101,102,102,104,104,108,109,111
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Calculate the sample mean (?⎯⎯⎯x¯), sample standard deviation (?s), and standard error (SE) of the students' scores. Round your answers to four decimal places.
Determine the ?t-critical value (?t) and margin of error (?m) for a 90% confidence interval. Round your answers to three decimal places.
What are the lower and upper limits of a 90% confidence interval? Round your answers to three decimal places.
?⎯⎯⎯=x¯=
?=s=
?t =
SE=SE=
?m =
lower limit:
upper limit:
Which is the correct interpretation of the confidence interval?
There is a 90% chance that the population mean is between 93.350 points and 100.050 points.
Shelia is 90% confident that the true population mean is between 93.350 points and 100.050 points.
Shelia is 90% confident that the true population mean is between 95.513 points and 99.887 points.
Shelia is certain that the true population mean is between 93.350 points and 100.050 points.
There is a 90% chance that the true population mean is between 95.513 points and 99.887 points.
Solution:
Sample size = n = 20
Part a) Calculate the sample mean , sample standard deviation ( s), and standard error (SE)
Formula:
Thus we need to make following table:
x | x^2 |
80 | 6400 |
81 | 6561 |
89 | 7921 |
90 | 8100 |
91 | 8281 |
91 | 8281 |
91 | 8281 |
94 | 8836 |
95 | 9025 |
95 | 9025 |
95 | 9025 |
101 | 10201 |
101 | 10201 |
102 | 10404 |
102 | 10404 |
104 | 10816 |
104 | 10816 |
108 | 11664 |
109 | 11881 |
111 | 12321 |
Thus
and
Part b) Determine the t-critical value (t) and margin of error ( m) for a 90% confidence interval.
df = n - 1 = 20 - 1 = 19
Two tail area = 1 - 0.90 = 0.10
t critical value = 1.729
Margin of Error is:
Part c) What are the lower and upper limits of a 90% confidence interval?
and
Part d) Which is the correct interpretation of the confidence interval?
Shelia is 90% confident that the true population mean is between 93.350 points and 100.050 points.