Question

In: Math

P(Z<z) z Mu Sigma x 0.2735 FALSE 202 65 FALSE 0.8615 FALSE 543 60 FALSE 0.0790...

P(Z<z) z Mu Sigma x
0.2735 FALSE 202 65 FALSE
0.8615 FALSE 543 60 FALSE
0.0790 FALSE 352 244 FALSE
0.3020 FALSE 552 348 FALSE
0.4139 FALSE 787 255 FALSE
0.9537 FALSE 643 499 FALSE
0.9127 FALSE 949 60 FALSE
0.7930 FALSE 68 66 FALSE
0.4808 FALSE 246 205 FALSE
0.3821 FALSE -93 4 FALSE
0.3747 FALSE 256 50 FALSE
0.0671 FALSE -123 6 FALSE
Instructions: Complete columns B and F. Don't round column F.
Notes: Skill with no specific practice set: Finding z and x for P(Z>z). These must be found by either subtracting from 1 or reversing sign of z.

Solutions

Expert Solution

Solution:

We are given that:

P(Z< z) and we have to find corresponding z values.
Also we are given that mean and Standard deviation values and we have to find corresponding x values.


We use excel command to find z values:

=NORM.S.INV( Probability )

=NORM.S.INV( 0.2735)

= -0.60226

= - 0.60

and for x values we use formula:

=NORM.INV( probability , Mean , SD )

=NORM.INV( 0.2735 , 202 , 65 )

=162.853

Or we can use Formula:

Thus we get:

P(Z<z) z Mu Sigma x
0.2735 -0.60226 FALSE 202 65 162.853 FALSE
0.8615 1.08708 FALSE 543 60 608.225 FALSE
0.079 -1.41183 FALSE 352 244 7.513 FALSE
0.302 -0.51866 FALSE 552 348 371.507 FALSE
0.4139 -0.21752 FALSE 787 255 731.531 FALSE
0.9537 1.68184 FALSE 643 499 1482.238 FALSE
0.9127 1.35757 FALSE 949 60 1030.454 FALSE
0.793 0.81687 FALSE 68 66 121.914 FALSE
0.4808 -0.04815 FALSE 246 205 236.130 FALSE
0.3821 -0.29997 FALSE -93 4 -94.200 FALSE
0.3747 -0.31943 FALSE 256 50 240.028 FALSE
0.0671 -1.49774 FALSE -123 6 -131.986 FALSE

To find x for P( Z > z) use following steps:

reverse the sign of z values and use these z values to find x values:

P(Z<z) z new z Mu Sigma x
0.2735 -0.60226 0.60226 FALSE 202 65 241.147 FALSE
0.8615 1.08708 -1.08708 FALSE 543 60 477.775 FALSE
0.079 -1.41183 1.41183 FALSE 352 244 696.487 FALSE
0.302 -0.51866 0.51866 FALSE 552 348 732.493 FALSE
0.4139 -0.21752 0.21752 FALSE 787 255 842.469 FALSE
0.9537 1.68184 -1.68184 FALSE 643 499 -196.238 FALSE
0.9127 1.35757 -1.35757 FALSE 949 60 867.546 FALSE
0.793 0.81687 -0.81687 FALSE 68 66 14.086 FALSE
0.4808 -0.04815 0.04815 FALSE 246 205 255.870 FALSE
0.3821 -0.29997 0.29997 FALSE -93 4 -91.800 FALSE
0.3747 -0.31943 0.31943 FALSE 256 50 271.972 FALSE
0.0671 -1.49774 1.49774 FALSE -123 6 -114.014 FALSE

Related Solutions

P(Z<z) z Mu Sigma x 0.2735 FALSE 202 65 FALSE 0.8615 FALSE 543 60 FALSE 0.0790...
P(Z<z) z Mu Sigma x 0.2735 FALSE 202 65 FALSE 0.8615 FALSE 543 60 FALSE 0.0790 FALSE 352 244 FALSE 0.3020 FALSE 552 348 FALSE 0.4139 FALSE 787 255 FALSE 0.9537 FALSE 643 499 FALSE 0.9127 FALSE 949 60 FALSE 0.7930 FALSE 68 66 FALSE 0.4808 FALSE 246 205 FALSE 0.3821 FALSE -93 4 FALSE 0.3747 FALSE 256 50 FALSE 0.0671 FALSE -123 6 FALSE Instructions: Complete columns B and F. Don't round column F. Notes: Skill with no specific...
X follows a normal distribution with mu = 4.7 and sigma = 1.1. P(3.05 < X...
X follows a normal distribution with mu = 4.7 and sigma = 1.1. P(3.05 < X < 3.93) to four decimal places is: 1) 0.6752 2) 0.1752 3) 0.3248 4) 0.8248
Let X ~ N(190; 23). Find: (a) P(X <= 213) (b) P(148 < X < 202)...
Let X ~ N(190; 23). Find: (a) P(X <= 213) (b) P(148 < X < 202) (c) The first quartile for X (d) The third quartile for X (e) the IQR for X (f) P(|X-190|> 34
which would evaluate to false? ((x&&!y ||z) || !z&&x) a. x and y are false b....
which would evaluate to false? ((x&&!y ||z) || !z&&x) a. x and y are false b. x and z are false c. z is false d. x y z are true e. x is false
find p(65<X<70)
find p(65<X<70)
Normal mu 722 sigma 189 xi P(X<=xi) 151 0.0013 263 0.0076 532 0.1574 721 0.4979 810...
Normal mu 722 sigma 189 xi P(X<=xi) 151 0.0013 263 0.0076 532 0.1574 721 0.4979 810 0.6793 961 0.8970 P(X<=xi) xi 0.11 490.1862 0.12 499.9275 0.24 588.5088 0.31 628.2843 0.38 664.2641 0.76 855.4912 0.89 953.8138 Use the cumulative normal probability excel output above (dealing with the amount of money parents spend per child on back-to-school items) to answer the following question. The probability is 0.38 that the amount spent on a randomly selected child will be between two values (in...
#65 Suppose Z ~ N(0, 1), and P(Z < z) = 0.9750. Find z. Enter your...
#65 Suppose Z ~ N(0, 1), and P(Z < z) = 0.9750. Find z. Enter your exact value from Table A4. If you use Excel instead, enter your value rounded to 2 decimal places #89 Suppose X ~ N(10, 2), and P(X < x) = 0.5. Find x. Enter your exact numerical value. #90 Suppose X ~ N(11, 4). Find P(X > 3). Round your answer to 4 decimal places. #60 Suppose X ~ N(100, 2). Find P(X < 98)....
If X(t), t>=0 is a Brownian motion process with drift mu and variance sigma squared for...
If X(t), t>=0 is a Brownian motion process with drift mu and variance sigma squared for which X(0)=0, show that -X(t), t>=0 is a Brownian Motion process with drift negative mu and variance sigma squared.
Suppose x is a normally distributed random variable with mu equals 43 and sigma equals 5....
Suppose x is a normally distributed random variable with mu equals 43 and sigma equals 5. Find a value x 0 of the random variable x that satisfies the following equations or statements. a. ​P(x less than or equals x 0​)equals0.8413 b. ​P(x greater thanx 0​)equals0.025 c. ​P(x greater thanx 0​) equals 0.95 d.​ P(28 less than or equals x less thanx 0​) equals 0.8630 e.​ 10% of the values of x are less than x 0. f.​ 1% of...
let R = Z x Z. P be the prime ideal {0} x Z and S...
let R = Z x Z. P be the prime ideal {0} x Z and S = R - P. Prove that S^-1R is isomorphic to Q.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT