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In the vertices of a square of the side 2 x10 ^ -9 four protons are...

In the vertices of a square of the side 2 x10 ^ -9 four protons are placed. A fifth proton is initially perpendicular to the square in its center, at a distance of 2 x 10 ^ -9 thereof. Calculate (a) the minimum initial velocity that the fifth proton needs to reach the center of the square, (b) its initial and final accelerations. (c) graph the potential energy of the proton as a function of its distance from the center of the square.

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genius_generous answered 2 years ago
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