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In the vertices of a square of side 2x10 ^ -7 four protons are placed. A...

In the vertices of a square of side 2x10 ^ -7 four protons are placed. A fifth proton is initially perpendicular to the square at its center at a distance of 2x10 ^ -9 m from it. Calculate (a) the minimum initial velocity of the fifth proton you need to get to the center of the square (b) your initial and final accelerations. (c) graph the potential energy of the proton as a function of its distance from the center of the square.

Solutions

Expert Solution

Solution-

a)

Electrostatic potential energy= kqq/r

K.E. needed to just get proton at the center is

So

So

b)

Initial and final acceleration depends on force action on an object

c)

CURVE

So as

genius_generous answered 5 months ago
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