In: Math
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(A)
Here the ANOVA table is given below
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Group 1 | 3 | 11.8 | 3.933333 | 0.213333 | ||
Group 2 | 3 | 8.9 | 2.966667 | 1.773333 | ||
Group 3 | 4 | 4.3 | 1.075 | 1.7025 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 14.93917 | 2 | 7.469583 | 5.757961 | 0.033223 | 4.737414 |
Within Groups | 9.080833 | 7 | 1.297262 | |||
Total | 24.02 | 9 |
Here for the group 1 and group 2
the value of LSD is
Here dFW = 7 so
t0.025, 7 = 3.4995
LSD(1-2) = 3.4995 * sqrt [1.297262 * (1/3 + 1/3)] = 3.2544
LSD(1-3) = 3.4995 * sqrt [1.297262 * (1/3 + 1/4)] = 3.0442
LSD(2-3) = 3.4995 * sqrt [1.297262 * (1/3 + 1/4)] =3.0442
(b) Here mean difference between group 1 and group 2 = 3.93-2.9667 = 0.9667
which is less than LSD so there is no significant difference.
Here mean difference between group 1 and group 3 = 3.93- 1.075 = 2.5853
which is less than LSD so there is no a significant difference.
Here mean difference between group 2 and group 3 = 2.9667 - 1.075 =1.8917
which is less than LSD so there is not a significant difference.
None of them is significant