How many grams of copper be deposited at the cathode of an electrolysis cell if an...

How many grams of copper be deposited at the cathode of an electrolysis cell if an electric current of 15 mA is applied for 1.0 h through an aqueous solution containing excess Cu2+ ions? Assume the process is 100°0 efficient.

Solutions

Expert Solution

According to Faraday's first law , W = (ECT) / 96500

Where W = mass of metal deposited = ?

E = Equivalent weight of Cu = 63.54 / 2

= 31.77

C = current = 15 mA = 15 x10^-3 A

t = time taken = 1.0 h

= 1.0x60x60 s

= 3600 s

Plug the values we get

W = ( 31.77 x 15x10^-3 x 3600 ) / 96500

= 0.018 g

Therefore the mass of copper deposited is 0.018 g

queen_honey_blossom answered 2 months ago

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