In: Chemistry
How many grams of copper be deposited at the cathode of an electrolysis cell if an electric current of 15 mA is applied for 1.0 h through an aqueous solution containing excess Cu2+ ions? Assume the process is 100°0 efficient.
According to Faraday's first law , W = (ECT) / 96500
Where W = mass of metal deposited = ?
E = Equivalent weight of Cu = 63.54 / 2
= 31.77
C = current = 15 mA = 15 x10-3 A
t = time taken = 1.0 h
= 1.0x60x60 s
= 3600 s
Plug the values we get
W = ( 31.77 x 15x10-3 x 3600 ) / 96500
= 0.018 g
Therefore the mass of copper deposited is 0.018 g