Question

Based on your copper solid used in RXN 1, how many grams of copper product should have been formed? Based on the copper solid in RXN 1, how many grams of the copper Hydroxide should have been formed in RXN 2? Based on the mass of copper used in RXN 1, how many grams of the zinc metal should have been used in RXN 5?

My mass of copper in RXN 1: .3595 grams

RXN1 : 4HN0₃ (aq) + Cu(s)-> Cu(NO₃)₂(aq) + 2H₂O (l) + 2NO₂ (g)

RXN 2: Cu(NO₃)₂(aq) + 2NaOH(aq) -> Cu(OH)₂(s) + 2NaNO_3(aq)

RXN 5: CuSO_4(aq)+ ZN(s) -> Cu (s) + Zn SO₄ (aq)       ( Mass of zinc in RXN 5: 3.00g)

Please show all work. I am confused on how to do this.

Answer 1

Reaction 1

4HN0_{3 (aq)} + Cu_(s)-> Cu(NO₃)_2(aq) + 2H₂O _(l) + 2NO_{2 (g)}

molar mass of Cu = 63.546 gm/mole that mean 1 mole of Cu = 63.546 gm

molar mass of Cu(NO₃)₂ = 187.56 gm/mole that mean 1 mole of Cu(NO₃)₂ = 187.56 gm

According to reaction 1 mole of Cu produce 1 mole of Cu(NO₃)₂ that mean 63.546 gm of Cu produce 187.56 gm Cu(NO₃)₂ then 0.3595 gm Cu produce 187.56 0.3595 /63.546 = 1.061 gm of Cu(NO₃)₂

Reaction 2

Cu(NO₃)_2(aq) + 2NaOH_(aq) -> Cu(OH)_2(s) + 2NaNO_3(aq)

molar mass of Cu(NO₃)₂ = 187.56 gm/mole that mean 1 mole of Cu(NO₃)₂ = 187.56 gm

molar mass of Cu(OH)₂ = 97.561 gm/mole that mean 1 mole of Cu(OH)₂ = 97.561 gm

According to reaction 1 mole of Cu(NO₃)₂ produce 1 mole of Cu(OH)₂ that mean 187.56 gm of Cu(NO₃)₂produce 97.561 gm Cu(OH)₂ then 1.061 gm Cu(NO₃)₂ produce 97.561 1.061 /187.56 = 0.5518 gm of Cu(OH)₂

Reaction 5

CuSO_4(aq)+ ZN_(s) -> Cu _(s) + Zn SO_{4 (aq)}

molar mass of Cu = 63.546 gm/mole that mean 1 mole of Cu = 63.546 gm

molar mass of Zn = 65.38 gm/mole that mean 1 mole of Zn = 65.38 gm

According to reaction 1 mole of Cu displace 1 mole Zn that mean 63.546 gm of Cu displace 65.38 gm of Zn then 0.3595 gm of Cu displace 0.3595 65.38 / 63.546 = 0.3698 gm of Zn used in reaction 5.