In: Statistics and Probability
1. Do you prefer taking test on paper or online? An college instructor believes the tests scores will be the same, on average. This instructor gave identical tests to two randomly sampled groups of 35 students. One group took the test on paper and the other took it online. The results are below. Test whether the test scores are the same at significance level 0.10. Your complete solution should include a comparative boxplot displaying a box for each group, over the same scale.
Paper
79 |
75 |
49 |
78 |
73 |
81 |
70 |
63 |
79 |
65 |
60 |
74 |
64 |
64 |
74 |
69 |
57 |
65 |
61 |
58 |
92 |
71 |
69 |
66 |
71 |
68 |
67 |
81 |
78 |
80 |
76 |
67 |
49 |
56 |
45 |
Online
79 |
75 |
71 |
81 |
56 |
72 |
49 |
75 |
63 |
81 |
74 |
72 |
71 |
73 |
83 |
59 |
78 |
65 |
53 |
47 |
63 |
82 |
81 |
76 |
65 |
82 |
78 |
76 |
65 |
72 |
85 |
84 |
81 |
50 |
79 |
Here is the data:
The provided sample means are shown below:
Also, the provided sample standard deviations are:
and the sample sizes are
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho:
Ha:
This corresponds to a two-tailed test, for which a t-test for two population means, with two independent samples, with unknown population standard deviations will be used.
(2) Rejection Region
Based on the information provided, the significance level is α=0.10, and the degrees of freedom are df=68.
Hence, it is found that the critical value for this two-tailed test is tc=1.668, for α=0.10 and df=68.
The rejection region for this two-tailed test is R={t:∣t∣>1.668}.
(3) Test Statistics
Since it is assumed that the population variances are equal, the t-statistic is computed as follows:
(4) Decision about the null hypothesis
Since it is observed that ∣t∣=1.166≤tc=1.668, it is then concluded that the null hypothesis is not rejected.
Using the P-value approach: The p-value is p=0.2479, and since p=0.2479≥0.10, it is concluded that the null hypothesis is not rejected.
(5) Conclusion
It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean μ1 is different than μ2, at the 0.10 significance level.
Confidence Interval
The 90% confidence interval is −7.084<μ1−μ2<1.255.
Graphically
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