A circular coil 20.0cm in diameter and containing nine loops lies flat on the ground. The...

A circular coil 20.0cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 8.00

Expert Solution

magnitude of magnetic field B = 8 x 10^-5T

diameter of coil = d = 20.0 cm ( 10^-2 m / cm)

= 0.20 m

radius of the coil r = d/2

= 0.10 m

area of the loop A = r²

= ( 3.14 ) ( 0.10 m)²

= 0.0314 m²

The angle between the normal to the coil and the field is 90.0^o - 57.0

genius_generous answered 9 months ago

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