In: Statistics and Probability
QUESTION 10
Questions 10 through 13 refer to the following:
Using the partially completed analysis of variance and table of means provided below, answer the following questions. Use the .05 significance level. All three groups have the same sample size.
| 
 Source  | 
 SS  | 
 df  | 
 MS  | 
 F  | 
| 
 Treatment  | 
 3.9302  | 
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| 
 Error  | 
 9.03  | 
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| 
 Total  | 
 26  | 
| 
 Group  | 
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| 
 A  | 
 B  | 
 C  | 
|
| 
 sample mean  | 
 278.3  | 
 275.4  | 
 274.5  | 
Find the value of LSD for comparing Groups A and B.
QUESTION 11
Is the difference between groups A and B significant?
| 
 yes  | 
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| 
 no  | 
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| 
 maybe?  | 
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| 
 Antidisestablishmentarianism  | 
QUESTION 12
What's the value of SSTR?
QUESTION 13
What's the value of SSE?
QUESTION 10
| 
 Source  | 
 SS  | 
 df  | 
 MS  | 
 F  | 
| 
 Treatment  | 
 70.98  | 
 2  | 
 35.49  | 
 3.9302  | 
| 
 Error  | 
 216.72  | 
 24  | 
 9.03  | 
|
| 
 Total  | 
 287.70  | 
 26  | 
DONE
Concept Base
Degrees of freedom
Treatment: Number if treatments (groups) – 1 = 3 – 1 = 2
Error: df for Total – df for Treatment = 26 (given) – 2 = 24
F = MSTr/MSE
So, MSTr = F x MSE = 3.9302 x 9.03 = 35.49
MSTr = SSTr/df, or
SSTr = MSTr x df = 35.49 x 2 = 70.98
Similarly, SSE = 9.03 (given) x 24 = 216.72
SST = SSTr + SSE = 70.98 + 216.72 = 287.70.
Value of LSD for comparing Groups A and B.
QUESTION 11
Value of LSD for comparing Groups A and B
Concept Base
| 
 Let n1 and n2 be the sample sizes for obtaining X1bar and X2bar.  | 
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| 
 LSDcrit = t(α/2)√[MSW{(1/n1) + (1/n2)}], where  | 
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| 
 t(α/2) = upper (α/2) percent point of t-distribution with  | 
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| 
 degrees of freedom = DF of MSW i.e., Error or Residual MS of ANOVA  | 
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 Decision: The difference, d = |X1bar - X2bar| is significant if  | 
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| 
 d > LSDcrit, as given above.  | 
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Now, the calculations
d = 278.3 – 275.4 = 2.9
n1 = n2 = 9
t(α/2) = upper 2.5% percent point of t-distribution with 24 degrees of freedom
= 2.064 [from Standard t-distribution Tables]
MSW = 9.03 [from ANOVA Table]
{(1/n1) + (1/n2)} = 2/9 = 0.2222
LSDcrit = 2.064√(9.03 x 0.2222)
= 2.923
Here the difference between d and LSDcrit is marginal. Hence, we conclude that the difference between the means of Group A and Group B is not significant. Answer
QUESTION 12
SSTR = 70.98 [from ANOVA Table] Answer
QUESTION 13
SSE = 216.72 [from ANOVA Table] Answer
DONE