In: Statistics and Probability
You roll 36 fair dice. How many ones do you expect to get?
We roll 36 dice so, n =36
Now in rolling a dice we get following outcomes
S= {1,2,3,4,5,6}
Now Probability of getting one in rolling a dice (P) = 1/6
Let getting one in rolling a dice is a success than
P(success) =1/6
P(failure) = 1-1/6 = 5/6
which follows bernoulli distribution with probability of success = 1/6
Now if we roll 36 dice then using approximation
We get a binomial distribution with parameter
n =36, p = 1/6
q=1-p = 5/6
Now , according to question we are calculating expected number of ones in 36 dice
Let X denotes the number of ones in 36 fair dice roll.
then X ~ Binomial(36,1/6)
Now,
E[X] = np
= 36*1/6
= 6 Answer
We expect to get 6 ones in rolling 36 fair dice.