In: Physics
Often times during volcano eruptions the clouds have large static charge buildups that cause lightning to happen. If a rock is ejected by the volcano and it flies to a height of 1795 m, and the clouds have a charge concentration of +40.0 C at a height of 3400 m and ?40.0 C at a height of 1000 m, what is the electric field at the ejected rock?
magnitude | 1 N/C |
direction | 2---Select---downwardupward |
Note that
E = kq/r^2
where
k = 8.99E+09 N m^2/C^2
q = the source charge 4.00E+01 C
r = the distance from the source charge =
1605 m
For the positive charge.
Thus,
E = -2.2405E+08 N/C [downward]
For the negative charge, note that
E = kq/r^2
where
k = 8.99E+09 N m^2/C^2
q = the source charge -4.00E+01 C
r = the distance from the source charge =
795 m
Thus,
E = -4.523E+08 N/C
[downward]
Thus, the net electric field is the sum of these two,
Enet = -6.76*10^8 N / C, DOWNWARD [FINAL ANSWER]