Question

In: Chemistry

Consider the three tubes below. Each contains a few drops of the color indicator bromothymol blue,...

Consider the three tubes below. Each contains a few drops of the color indicator bromothymol blue, which is yellow in acidic solutions and blue in basic solutions. One tube contains a solution of ammonium chloride, one contains ammonium acetate, and the third contains sodium acetate. Which beaker contains which salt? Explain your reasoning.

1st tube = yellow

2nd tube = green

3rd tube = blue

Solutions

Expert Solution

first consider NH4Cl

we know that

NH4Cl is obtained by the reaction

HCl + NH3 ---> NH4Cl

it is a salt of strong acid HCl and weak base NH3

since

NH3 is a weak base , its conjugate NH4+ will be a strong acid

it undergoes hydrolysis in the solution

NH4+ + H20 ---> H30+ + NH3

since it produces H30+

the solution is acidic

the color will be yellow

1st tube ---> ammonium chloride

now

consider CH3COONa

we know that

it is a salt of weak acid CH3OOH and strong base NaOH

since

CH3COOH is a weak acid , its conjugate CH3C00- will be a strong base

it undergoes hydrolysis in the solution

CH3COO- + H20 ---> CH3COOH + OH-

since it produces OH-

the solution is basic

the color will be blue

3rd tube ---> sodium acetate

finally

ammonium acetate

it is a salt of weak acid CHCOOH and weak base NH3

the pH of the solution depends on the Ka values and the temperature

it should be in 2nd tube

1st tube ---> ammonium chloride

2nd tube ---> ammonium acetate

3rd tube ----> sodium acetate

queen_honey_blossom answered 3 months ago

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