Question

In: Chemistry

Consider the three tubes below. Each contains a few drops of the color indicator bromothymol blue,...

Consider the three tubes below. Each contains a few drops of the color indicator bromothymol blue, which is yellow in acidic solutions and blue in basic solutions. One tube contains a solution of ammonium chloride, one contains ammonium acetate, and the third contains sodium acetate. Which beaker contains which salt? Explain your reasoning.

1st tube = yellow

2nd tube = green

3rd tube = blue

Expert Solution

first consider NH4Cl

we know that

NH4Cl is obtained by the reaction

HCl + NH3 ---> NH4Cl

it is a salt of strong acid HCl and weak base NH3

since

NH3 is a weak base , its conjugate NH4+ will be a strong acid

it undergoes hydrolysis in the solution

NH4+ + H20 ---> H30+ + NH3

since it produces H30+

the solution is acidic

so

the color will be yellow

So

1st tube ---> ammonium chloride

now

consider CH3COONa

we know that

it is a salt of weak acid CH3OOH and strong base NaOH

since

CH3COOH is a weak acid , its conjugate CH3C00- will be a strong base

it undergoes hydrolysis in the solution

CH3COO- + H20 ---> CH3COOH + OH-

since it produces OH-

the solution is basic

so

the color will be blue

So

3rd tube ---> sodium acetate

finally

ammonium acetate

it is a salt of weak acid CHCOOH and weak base NH3

the pH of the solution depends on the Ka values and the temperature

so

it should be in 2nd tube

so

1st tube ---> ammonium chloride

2nd tube ---> ammonium acetate

3rd tube ----> sodium acetate

queen_honey_blossom answered 10 months ago

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