Question

The solubility product of Hg₂Cl₂ at T=298 K is 1.2 x 10^-18. What is the molar solubility of this salt?

		2.0 x 10-9 mol L-1
		6.9 x 10-7 mol L-1
		There is not enough information to answer this question

Answer 1

    Hg2Cl2(s) -------------> Hg₂^2+ (aq) + 2Cl^- (aq)

                                          s                    2s

   Ksp    = [Hg^+]^2[Cl^-]^2

             = (s) * (2s)^2

1.2*10^-18   = 4s^3

s^3            = 1.2*10^-18/4

S^3           = 0.3*10^-18

S              = 6.72*10^-7

solubility     = 6.7*10^-7 mole/L

6.9 x 10^-7 mol L^-1 >>>>>answer