Question
In: Chemistry
The stopcock connecting a 4.10 L bulb containing krypton gas at a pressure of 4.80 atm,...
The stopcock connecting a 4.10 L bulb containing krypton gas at a pressure of 4.80 atm, and a 3.21 L bulb containing carbon dioxide gas at a pressure of 2.22 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is _____atm
Solutions
Expert Solution
Kr CO2
PKr = 4.8atm PCo2 = 2.22atm
VKr = 4.1L VCo2 = 3.21L
P = PKr *VKr + PCO2*VCO2/VKr + VCo2
= 4.8*4.1+2.22*3.21/4.1+3.21
= 26.8062/7.31 = 3.67atm >>>>answer
queen_honey_blossom answered 2 years agoRelated Solutions
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