Question

In: Chemistry

How much heat is required to convert solid ice with a mass of 750 g and...

How much heat is required to convert solid ice with a mass of 750 g and at a temperature of -26.5 °C to liquid water at a temperature of 72.0 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)

Solutions

Expert Solution

mass of ice = 750g = 0.75Kg

ice converted to 00C water  

                         q1   = mcT

                                 = 0.75*2100*(0-(-26.5)

                                 = 0.75*2100*26.5

                                 = 41737.5J   = 41.7375KJ

heat of fustion ice

                            q2   = mH vap

                                    = 0.75*334   = 250.5KJ

00C water converted to 720C

                    q3        = mcT

                                = 0.75*4186.8*(72-0)   = 226087.2J = 226.087Kj

Total heat energy q = q1 +q2 + q3

                                    = 41.7375 +250.5+226.087   = 518.324KJ >>>>answer


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