How much heat is required to convert solid ice with a mass of 750 g and...

How much heat is required to convert solid ice with a mass of 750 g and at a temperature of -26.5 °C to liquid water at a temperature of 72.0 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)

Expert Solution

mass of ice = 750g = 0.75Kg

ice converted to 0⁰C water

q1 = mcT

= 0.75*2100*(0-(-26.5)

= 0.75*2100*26.5

= 41737.5J = 41.7375KJ

heat of fustion ice

q2 = mH vap

= 0.75*334 = 250.5KJ

0⁰C water converted to 72⁰C

q3 = mcT

= 0.75*4186.8*(72-0) = 226087.2J = 226.087Kj

Total heat energy q = q1 +q2 + q3

= 41.7375 +250.5+226.087 = 518.324KJ >>>>answer

queen_honey_blossom answered 2 years ago

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