In: Chemistry
***Part1: Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)
( )CO2 + ( )H2O →( ) CH4 + ( )O2
( )Co(NO3)3 +( ) (NH4)2S → ( )Co2S3 +( ) NH4NO3
( ) NH3 + ( )O2 → ( )NO + ( )H2O
( ) NaCl + ( )H2SO4 →( ) Na2SO4 + ( )HCl
***Part2 : Consider the complete combustion of 2.91×10-4 moles of C6H12O6 with excess oxygen.
A. Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)
( ) C6H12O6 + ( )O2 → ( )CO2 + ( )H2O
B. How many moles of water are produced in this reaction? [ ]
***Part3 : Determine the mass of carbon dioxide (in g) produced from the complete combustion of 8.34×10-1 g of C8H14O with excess oxygen.
[ ]
***Part1: Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)
( 1 )CO2 + ( 2 )H2O →( 1 ) CH4 + ( 2 )O2
( 2 )Co(NO3)3 +( 3 ) (NH4)2S → ( 1 )Co2S3 +( 6 ) NH4NO3
( 4 ) NH3 + ( 5 )O2 → ( 4 )NO + ( 6 )H2O
( 2 ) NaCl + ( 1 )H2SO4 →( 1 ) Na2SO4 + ( 2 )HCl
***Part2 : Consider the complete combustion of 2.91×10-4 moles of C6H12O6 with excess oxygen.
A. Balance the following chemical equation using the lowest possible whole number coefficients. (Enter coefficients of one - blanks will be marked incorrect.)
( 1 ) C6H12O6 + ( 9 )O2 → ( 6 )CO2 + ( 6 )H2O
B. How many moles of water are produced in this reaction? [ ]
2.91×10-4 moles of C6H12O6
(2.91×10-4)*6 moles of H"O = 0.001746
***Part3 : Determine the mass of carbon dioxide (in g) produced from the complete combustion of 8.34×10-1 g of C8H14O with excess oxygen.
[ ]
( 1 ) C6H12O6 + ( 9 )O2 → ( 6 )CO2 + ( 6 )H2O
1 mol of carb will give you 6 mol of CO
MW of C6H12O6 = 180
mol = mass/MW = 8.34*10^-1 / (180) = 0.00463 mol of C6H12O6
expect 6 times that of CO2
6*0.00463 = 0.0278 mol of CO2
MW CO2 = 44
mass = mol*MW = 44*0.0278 = 1.2232 grams of CO2