Q22 Variable s is defined as a string vector. We display the first a couple of...

Q22 Variable s is defined as a string vector. We display the first a couple of elements: s = [ ′′height′′ , “12.5” , “weight ′′ , ′′103-9′′ , ′′NWD′′, ... ].

Code to do the following.

replace all elements “height” with “dimension” for s. Solve this using loop
replace all elements “height” with “dimension” for s. Solve this without using loop
create a new character vector s1, which concatenate all elements of s horizontally. That is, s1 = ′′height12.5weight 103-9NWD...”.

I need help to solve this in MATLAB programming please.....

Expert Solution

s = [ "height" , "12.5" , "weight" , "103-9" , "NWD","height"];
%replace all elements "height” with “dimension” for s. Solve this using loop
for i=1:length(s)
if s(i)=="height"
s(i)="dimension";
end
end
s
s = [ "height" , "12.5" , "weight" , "103-9" , "NWD","height"];
%replace all elements "height” with “dimension” for s. Solve this without using loop
s(s=="height")="dimension"
s = [ "height" , "12.5" , "weight" , "103-9" , "NWD","height"];
%create a new character vector s1, which concatenate all elements of s horizontally. That is, s1 = ′′height12.5weight 103-9NWD...".
s1='';
for i=s
s1=[s1,char(i)];
end
s1

venereology answered 11 months ago

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