I'm not understanding quite how to do this type of problem. The problem states: What is...

I'm not understanding quite how to do this type of problem. The problem states: What is the enthalpy change produced by the reaction of 50.0 g Fe2O3 with 50.0 g Al according to the equation below?

Fe2O3(s) + 2Al(s) => Al2O3(s) + 2Fe(s) Delta H = -851.5 kJ

Please show me how to do this!

Expert Solution

moles of Fe2O3 = mass / molar mass of Fe2O3

= 50 / 159.69

= 0.313

moles of Al = 50 / 27 = 1.852

Fe2O3(s) + 2Al(s) --------------------> Al2O3(s) + 2Fe(s) Delta H = -851.5 kJ

1 mol 2 mol 1 mol

0.313 1.852

here limiting reagent is Fe2O3 . so heat formed according to that.

1 mol Fe2O3 ------------------- delta H = - 851.5 kJ

0.313 mol Fe2O3 ------------- delta H = ??

heat formed = - 266.5 kJ

queen_honey_blossom answered 10 months ago

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