Question

A sample of neon initially has a volume of 2.50 L at 110 ∘C. What is the new temperature, in ∘C, when the volume of the sample is changed at constant pressure to each of the following?

5.55 L

1.15×10³ mL

9.80 L

3.00×10³ mL

Answer 1

Initial                                                               final

V1 = 2.5L                                                     V2 = 5.55L

T1   = 110+273 = 383K                              T2 =

     V1/T1   = V2/T2

            T2   = V2T1/V1

                    = 5.55*383/2.5   = 850.26K   = 850.26-273   = 577.26⁰C

Initial                                                               final

V1 = 2.5L   = 2500ml                                    V2 = 1.15*10^3 ml   = 1150ml

T1   = 110+273 = 383K                              T2 =

     V1/T1   = V2/T2

            T2   = V2T1/V1

                    = 1150*383/2500 = 176.18K   = 176.18-273   = -96.82⁰C

Initial                                                               final

V1 = 2.5L                                                     V2 = 9.8L

T1   = 110+273 = 383K                              T2 =

     V1/T1   = V2/T2

    T2   = V2T1/V1
                    = 9.8*383/2.5    = 1501.35K    = 1501.35-273   = 1228.35⁰C

Initial                                                               final

V1 = 2.5L   = 2500ml                                    V2 = 3*10^3 ml   = 3000ml

T1   = 110+273 = 383K                              T2 =

     V1/T1   = V2/T2

            T2   = V2T1/V1

                    = 3000*383/2500     = 459.6K   = 459.6-273   = 186.6⁰C