Question

A sample containing 19.2 g of O2 gas has a volume of 15 L. What is the new volume if 0.500 mole of O2 gas is added, at constant pressure and temperature?

27.5 L

11.5 L

19.8 L

32.5 L

2) The mechanical process of breathing is a good illustration of:

Group of answer choices

Charles Law

Dalton’s Law

Boyle’s Law

Gay-Lussac’s Law

Answer 1

To calculate the final volume after the addition of 0.5 mol of oxygen to the container containing 19.2 g of oxygen we have to use avogadro's law which states that at constant temperature and pressure the volume of the gas is directly proportional to the moles of the gas.

So initial moles(n1 ) = 0.6 moles

Final moles (n2 ) = 0.5+0.6 = 1.1 moles

Initial volume = 15 L

Final volume = 15* 1.1 / 0.6 = 27.5 L.

Ans 2- Since the breathing is mechanical process which has generally two phases i.e inhalation and exhalation and depend on the volume of the chest. As we intake or exhale during breathing the volume changes so according to Boyles law if volume changes the pressure also changes that means pressure inside chest also changes.

Therefore the answer is Boyles law.