The table below summarizes the mean psychological distress score of persons who are married to or cohabiting with a romantic partner and those who are not. Psychological distress is a scale of feelings of depression and anxiety, ranging from 0 to 24, where higher scores indicate more distress. In answering these questions, show all of your work.

1. Construct a 95% confidence interval for psychological distress for respondents who are married to or cohabiting with a romantic partner.

2. Construct a 95% confidence interval for psychological distress for respondents who are not in a romantic relationship.

3. Compare the relative width of these two confidence intervals. Why do they differ?

4. Interpret one of these confidence intervals

5. Construct a 68% interval for respondents who are married to or cohabiting with a romantic partner.

Confidence intervals, effect sizes, and Valentine’s Day spending: According to the Nielsen Company, Americans spend $345 million on chocolate during the week of Valentine’s Day. Let’s assume that we know the average married person spends $45, with a population standard deviation of $16. In February 2009, the U.S. economy was in the throes of a recession. Comparing data for Valentine’s Day spending in 2009 with what is generally expected might give us some indication of the attitudes during the recession. a. Compute the 95% confidence interval for a sample of 18 married people who spent an average of $38. b. How does the 95% confidence interval change if the sample mean is based on 180 people? c. If you were testing a hypothesis that things had changed under the financial circumstances of 2009 as compared to previous years, what conclusion would you draw in part (a) versus part (b)? d. Compute the effect size based on these data and describe the size of the effect.

A certain data distribution has a mean of 18 and a standard deviation of 3

Wha, is the value would have a Z-score of -3.2?

Assuming that the distribution is normal, use the Empirical Rule to determine what proportion of this distribution would be found to be between 15 and 24

Assuming that the distribution is normal, use the Empirical Rule to determine what proportion of his distribution would be found to be between 12 and 15

Now imagine that this distribution is NOT guaranteed to be normally distributed. What would be the minimum proportion of this distribution that might be found between 13.5 and 22.5?

In one year, there were 17,737 fatal injuries in California, and 11,149 of them were unintentional. Using the data from this year, construct a 98% confidence interval estimate of the percentage of California fatal injuries that are unintentional. Interpret the interval as well.

Use the accompanying data set to complete the following actions.

a. Find the quartiles.

b. Find the interquartile range.

c. Identify any outliers.

61 61 63 64 63 64 58 55 65 65 59 59 60 57 77

Briefly compare and contrast the NPV, PI and IRR criteria. What are the advantages and disadvantages of using each of these methods?

) A measurement is normally distributed with ?=30 μ = 30 and ?=6 σ = 6 . Round answers below to three decimal places. (a) The mean of the sampling distribution of ?¯ x ¯ for samples of size 11 is: (b) The standard deviation of the sampling distribution of ?¯ x ¯ for samples of size 11 is:

The mean incubation time for a type of fertilized egg kept at a certain temperature is 22 days. Suppose that the incubation times are approximately normally distributed with a standard deviation of 1 day. Complete parts​ (a) through​ (b) below. ​(a) Find and interpret the probability that a randomly selected fertilized egg hatches in less than 20 days. The probability that a randomly selected fertilized egg hatches in less than 20 days is ______ . ​(Round to four decimal places as​ needed.) Interpret this probability.

Select the correct choice below and fill in the answer box to complete your choice. ​(Round to the nearest integer as​ needed.) A. If 100 fertilized eggs were randomly​ selected, _____ of them would be expected to hatch in less than 20 days.

B. If 100 fertilized eggs were randomly​ selected, exactly ____ would be expected to hatch on day 20.

C. In every group of 100 fertilized​ eggs, ____ eggs would be expected to hatch in less than 20 days.

​(b) Find and interpret the probability that a randomly selected fertilized egg takes over 24 days to hatch

. The probability that a randomly selected fertilized egg takes over 24 days to hatch is ____. ​(Round to four decimal places as​ needed.) Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. ​(Round to the nearest integer as​ needed.)

A. If 100 fertilized eggs were randomly​ selected, exactly ____would be expected to hatch on day 24.

B. In every group of 100 fertilized​ eggs, _____ eggs would be expected to hatch in more than 24 days.

C. If 100 fertilized eggs were randomly​ selected, _____ of them would be expected to take more than 24 days to hatch. ​(

c) Find and interpret the probability that a randomly selected fertilized egg hatches between 21 and 22 days.

The probability that a randomly selected fertilized egg hatches between 21 and 22 days is nothing. ​(Round to four decimal places as​ needed.) Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. ​(Round to the nearest integer as​ needed.)

A. If 100 fertilized eggs were randomly​ selected, exactly ____ would be expected to hatch on day 21 or on day 22.

B. If 100 fertilized eggs were randomly​ selected, ____ of them would be expected to hatch between 21 and 22 days.

C. In every group of 100 fertilized​ eggs, ____ eggs would be expected to hatch between 21 and 22 days.

​(d) Would it be unusual for an egg to hatch in less than 19 ​days? Why? The probability of an egg hatching in less than 19 days is ____, so it ▼ would , or would not be​ unusual, since the probability is ▼ greater , or less than 0.05. ​(Round to four decimal places as​ needed.)

1. The following table compares musical genre preference with preferred leisure activity among Mary's goats.

1. Complete a marginal relative frequency distribution above.
2. What proportion of Mary's goats enjoy peaceful activities (reading, eating flowers)?
3. Does it seem that musical preference and preferred leisure activity are independent? Justify your answer.

Suppose the accompanying summary statistics for a measure of social marginality for samples of youths, young adults, adults, and seniors appeared in a research paper. The social marginality score measured actual and perceived social rejection, with higher scores indicating greater social rejection.

For purposes of this exercise, assume that it is reasonable to regard the four samples as representative of the U.S. population in the corresponding age groups and that the distributions of social marginality scores for these four groups are approximately normal with the same standard deviation.

Is there evidence that the mean social marginality scores are not the same for all four age groups? Test the relevant hypotheses using

α = 0.01.

Calculate the test statistic. (Round your answer to two decimal places.)

F =

What can be said about the P-value for this test?

P-value > 0.1000.050 < P-value < 0.100    0.010 < P-value < 0.0500.001 < P-value < 0.010P-value < 0.001

What can you conclude?

Reject H₀. There is convincing evidence that the mean social marginality scores are not the same for all four age groups.Fail to reject H₀. There is not convincing evidence that the mean social marginality scores are not the same for all four age groups.    Fail to reject H₀. There is convincing evidence that the mean social marginality scores are not the same for all four age groups.Reject H₀. There is not convincing evidence that the mean social marginality scores are not the same for all four age groups.

You may need to use the appropriate table in Appendix A to answer this question.

Sleep – College Students (Raw Data, Software Required): Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7.0 hours per night. You randomly select 35 college students and survey them on the number of hours of sleep they get per night. The data is found in the table below. You want to construct a 99% confidence interval for the mean hours of sleep for all college students. You will need software to answer these questions. You should be able to copy the data directly from the table into your software program.

(a) What is the point estimate for the mean nightly hours of sleep for all college students? Round your answer to 2 decimal places.

(b) Construct the 99% confidence interval for the mean nightly hours of sleep for all college students. Round your answers to 2 decimal places.

Are you 99% confident that the mean nightly hours of sleep for all college students is below the average for all people of 7.0 hours per night? Why or why not?

Yes, because 7.0 is above the upper limit of the confidence interval for college students.

No, because 7.0 is below the upper limit of the confidence interval for college students.    

Yes, because 7.0 is below the upper limit of the confidence interval for college students.

No, because 7.0 is above the upper limit of the confidence interval for college students.

A person’s muscle mass is expected to be associated with age. Some people also thought exercise time would be associated with the muscle mass. To explore the potential relationships between muscle mass and age, muscle mass and exercise time, a nutritionist randomly selected 20 women from a population of women with age ranging from 40 to 80 years old, and measured their muscle mass (a score without unit) and exercise time (hours per month)

Using the regression equation representing the SIGNIFICANT relationship, make the following predictions: [of note: based on the regression model you chose, information for one of Age and ExcercieTime is not needed for prediction, but you should make your own decision on which variable is not needed!] The expected Muscle Mass (the mean) for Women at Age= 65 and ExerciseTime = 20; The expected difference in Muscle Mass between women with Age = 55 and ExcerciseTme =23 and women with Age = 58 and ExcerciseTime=25.

A professor is interested in knowing if the number of absences a student has in the semester is a good indication of how well a student does on the final exam. At the end of the year, the professor compares absence rates and exam grades for eight students. The data she found are as follows.

What is the null hypothesis?

What is the research hypothesis?

Calculate the Pearson's correlation coefficient.

Calculate t.

Is your correlation statistically significant and, if so, at what level?

What are your conclusions about the null hypothesis?

Suppose Motorola wishes to estimate the mean talk time for its V505 camera phone before the battery must be recharged. In a random sample of 35 phones, the sample mean talk time was 325 minutes.

(a) Why can we say that the sampling distribution of x̄ is approximately normal?

(b) Construct a 94% confidence interval for the mean talk time for all Motorola V505 camera phones, assuming that σ = 31 minutes. Interpret this interval.

(c) Construct a 98% confidence interval for the mean talk time for all Motorola V505 camera phones, assuming that σ = 31 minutes. Interpret this interval.

(d) How many phones would Motorola need to test to estimate the mean talk time for all V505 camera phones within 5 minutes with 95% confidence?

Show work. You can use technology.

1) We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following.

Each card will have:
i) One rank from 1 to 16.
ii) One of 5 different suits.

Hence, there are 80 cards in the deck with 16 ranks for each of the 5 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards!

The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get. a) How many different ways are there to get any 5 card hand?
The number of ways of getting any 5 card hand is
DO NOT USE ANY COMMAS

b)How many different ways are there to get exactly 1 pair (i.e. 2 cards with the same rank)?
The number of ways of getting exactly 1 pair is
DO NOT USE ANY COMMAS

What is the probability of being dealt exactly 1 pair?
Round your answer to 7 decimal places.


c) How many different ways are there to get exactly 2 pair (i.e. 2 different sets of 2 cards with the same rank)?
The number of ways of getting exactly 2 pair is
DO NOT USE ANY COMMAS

What is the probability of being dealt exactly 2 pair?
Round your answer to 7 decimal places.


d) How many different ways are there to get exactly 3 of a kind (i.e. 3 cards with the same rank)?
The number of ways of getting exactly 3 of a kind is
DO NOT USE ANY COMMAS

What is the probability of being dealt exactly 3 of a kind?
Round your answer to 7 decimal places.


e) How many different ways are there to get exactly 4 of a kind (i.e. 4 cards with the same rank)?
The number of ways of getting exactly 4 of a kind is
DO NOT USE ANY COMMAS

What is the probability of being dealt exactly 4 of a kind?
Round your answer to 7 decimal places.


f) How many different ways are there to get exactly 5 of a kind (i.e. 5 cards with the same rank)?
The number of ways of getting exactly 5 of a kind is
DO NOT USE ANY COMMAS