Compute the annual standard deviation of returns for all countries from 1980 – 1981
Year | Month | Australia | Canada | France | Germany | Italy |
1980 | 7 | -0.0026889 | 0.0546111 | -0.0204165 | 0.0369633 | 0.1278857 |
1980 | 8 | 0.0407999 | -0.0117627 | 0.0244608 | -0.0230018 | 0.0696608 |
1980 | 9 | 0.060746 | 0.0135679 | 0.0113528 | -0.0190223 | 0.1420983 |
1980 | 10 | 0.0585204 | -0.0220067 | 0.0920545 | -0.0205731 | 0.2766413 |
1980 | 11 | -0.0175011 | 0.0490367 | -0.0163204 | -0.0030604 | -0.0968726 |
1980 | 12 | -0.030612 | -0.074856 | -0.0757283 | -0.0210946 | 0.0017446 |
1981 | 1 | -0.0965194 | -0.0119725 | -0.0590439 | -0.034434 | 0.1904963 |
1981 | 2 | -0.0241678 | -0.0322855 | 0.0308526 | -0.0096864 | 0.0908233 |
1981 | 3 | 0.0816266 | 0.0492637 | 0.0112111 | 0.0099601 | 0.0358859 |
1981 | 4 | -0.0156632 | -0.0168862 | -0.0607607 | 0.0350148 | 0.1014527 |
1981 | 5 | -0.0034859 | 0.0154803 | -0.1894615 | -0.0372021 | 0.0531986 |
1981 | 6 | -0.0324157 | -0.0358805 | -0.0759704 | 0.0361752 | -0.2164954 |
1981 | 7 | -0.1098754 | -0.05526 | 0.1138425 | -0.0065494 | -0.092925 |
1981 | 8 | -0.0136848 | -0.0340705 | 0.0249309 | -0.0462012 | 0.1319221 |
1981 | 9 | -0.1024419 | -0.1480877 | -0.0313814 | -0.0480223 | -0.1772388 |
1981 | 10 | -0.0587205 | -0.0334613 | -0.0514094 | -0.015371 | -0.051872 |
1981 | 11 | 0.0683676 | 0.0768831 | 0.0250603 | 0.0186473 | 0.0455291 |
1981 | 12 | -0.0010473 | -0.0444019 | -0.0153722 | -0.0308835 | -0.016512 |
In: Math
Question 1:
Number of Order |
Frequency |
10-12 13-15 16-18 19-21 |
4 12 20 14 |
n=50 |
b. "Fits", a designer dress retailer specialising in ladies' formal wear, is currently in the process of re-ordering a batch of formal black dinner dresses. From its records of the last 100 sales, the following statistics on the dress sizes sold were calculated:
Mean(x) = 8.75 Md= 7.5 Mo = 8
Which measure of central tendency best describes the average size of dresses sold?
c. Suppose the probability that a house of a certain type will burn down in any 12-month period is 0.004. An insurance company offers to sell the owner of such a house a $120, 000 one-year term fire-insurance policy for a premium of $690. What is the company's expected gain from such a contract?
In: Math
A scientist working for a large agriculture company is interested in comparing the effect of various feed additives on the growth of chickens. Chickens were given feed supplemented with either soy, cornmeal, whey, linseed, or cricket flour. Their current diet is feed with a soy supplement. After 12 weeks on the diet, each chicken was weighed and the value (in grams) was recorded in the table below. Analyze the data to determine if there is a difference in chicken weight between the different additives and if so, which supplement is the most effective.
Supplement Type |
||||
Soy |
Cornmeal |
Whey |
Linseed |
Cricket |
43.5 |
15.2 |
50.4 |
115.9 |
17.1 |
60.1 |
23.4 |
63.2 |
75.5 |
21.5 |
45.1 |
19.7 |
91.3 |
113.4 |
13.5 |
47.4 |
13.4 |
36.3 |
53.4 |
13.1 |
18.1 |
16.9 |
87.4 |
103.5 |
25.3 |
29.1 |
11.4 |
27.7 |
136.6 |
32.3 |
a. Was a pretest performed? If so, fill in the values in the table.
Test type |
|
H0 |
|
HA |
|
Crit/Calc or exact p-value |
If not, explain why:
b. What was the conclusion of your pre-test? Do you need to transform your data? If so, fill in the transformation you used and your new critical/calculated value or new p-value.
Conclusion:
Transformation |
|
New Calc/Crit or p-value |
c. What are the null and alternative hypotheses for your main test?
d. Complete the ANOVA table:
H0 |
|
HA |
V ariance source |
df |
SS |
MS |
F |
P-value |
Among |
|||||
Within |
|||||
Total |
e. What conclusions can you draw? Do you need to do any post-hoc testing?
f. If you need to do post-hoc testing, fill in the blank cells in the table below with: which post- hoc test you chose and the p-values for each pair of comparisons. Note: the format of the table is generic and saves space; it is not meant to imply a specific test.
Post-hoc Test: |
||||
Soy |
Cornmeal |
Whey |
Linseed |
|
Cricket |
||||
Linseed |
||||
Whey |
||||
Cornmeal |
g. Plot your data. Based on the results of your ANOVA and post-hoc testing, what is your biological conclusion? Use the plot to be as specific as possible.
In: Math
How could an assignment problem be solved using the transportation approach? What condition will make the solution to this problem difficult?
Please give a typed answer and focus on the second part of the question.
In: Math
What would be the value of your portfolio today (i.e., in 1981), if you had invested $100 in the stock market index for each country in July, 1980. Report the value of your portfolio for each country separately.
Year | Month | Australia | Canada | France | Germany | Italy |
1980 | 7 | -0.0026889 | 0.0546111 | -0.0204165 | 0.0369633 | 0.1278857 |
1980 | 8 | 0.0407999 | -0.0117627 | 0.0244608 | -0.0230018 | 0.0696608 |
1980 | 9 | 0.060746 | 0.0135679 | 0.0113528 | -0.0190223 | 0.1420983 |
1980 | 10 | 0.0585204 | -0.0220067 | 0.0920545 | -0.0205731 | 0.2766413 |
1980 | 11 | -0.0175011 | 0.0490367 | -0.0163204 | -0.0030604 | -0.0968726 |
1980 | 12 | -0.030612 | -0.074856 | -0.0757283 | -0.0210946 | 0.0017446 |
1981 | 1 | -0.0965194 | -0.0119725 | -0.0590439 | -0.034434 | 0.1904963 |
1981 | 2 | -0.0241678 | -0.0322855 | 0.0308526 | -0.0096864 | 0.0908233 |
1981 | 3 | 0.0816266 | 0.0492637 | 0.0112111 | 0.0099601 | 0.0358859 |
1981 | 4 | -0.0156632 | -0.0168862 | -0.0607607 | 0.0350148 | 0.1014527 |
1981 | 5 | -0.0034859 | 0.0154803 | -0.1894615 | -0.0372021 | 0.0531986 |
1981 | 6 | -0.0324157 | -0.0358805 | -0.0759704 | 0.0361752 | -0.2164954 |
1981 | 7 | -0.1098754 | -0.05526 | 0.1138425 | -0.0065494 | -0.092925 |
1981 | 8 | -0.0136848 | -0.0340705 | 0.0249309 | -0.0462012 | 0.1319221 |
1981 | 9 | -0.1024419 | -0.1480877 | -0.0313814 | -0.0480223 | -0.1772388 |
1981 | 10 | -0.0587205 | -0.0334613 | -0.0514094 | -0.015371 | -0.051872 |
1981 | 11 | 0.0683676 | 0.0768831 | 0.0250603 | 0.0186473 | 0.0455291 |
1981 | 12 | -0.0010473 | -0.0444019 | -0.0153722 | -0.0308835 | -0.016512 |
In: Math
The following data is representative of that reported in an article on nitrogen emissions, with x = burner area liberation rate (MBtu/hr-ft2) and y = NOx emission rate (ppm):
x | 100 | 125 | 125 | 150 | 150 | 200 | 200 | 250 | 250 | 300 | 300 | 350 | 400 | 400 |
y | 140 | 140 | 170 | 210 | 200 | 330 | 280 | 390 | 440 | 450 | 400 | 590 | 610 | 660 |
(a) Assuming that the simple linear regression model is valid,
obtain the least squares estimate of the true regression line.
(Round all numerical values to four decimal places.)
y =
(b) What is the estimate of expected NOx
emission rate when burner area liberation rate equals 215? (Round
your answer to two decimal places.)
ppm
(c) Estimate the amount by which you expect NOx
emission rate to change when burner area liberation rate is
decreased by 60. (Round your answer to two decimal places.)
ppm
(d) Would you use the estimated regression line to predict emission
rate for a liberation rate of 500? Why or why not?
Yes, the data is perfectly linear, thus lending to accurate predictions.
Yes, this value is between two existing values.
No, this value is too far away from the known values for useful extrapolation.
No, the data near this point deviates from the overall regression model.
In: Math
1. Kelly and Veronica are two teachers in a math class who attend class independently of one another. For Friday classes, there is a .70 probability that kelly will come to class, while there is a .40 probability that Veronica will come to class. For a Friday class, what is the probability neither Kelly nor Veronica will be there?
2. The weights of newborn baby twin girls have an approximately normal distribution with a mean of 8.0 pounds and a standard deviation of 1.5 pounds. A doctor tells the family that one of the baby twin girl has a weight at the 30th percentile. Which of the following is closest to this baby's weight? (show work please)
A, 7.2
B 8.5
C 7.7
D 8.9
In: Math
Rejection Region
After reviewing data from a sample, an inference can be made about the population. For example,
Find a data set on the internet. Some suggested search terms: Free Data Sets, Medical Data Sets, Education Data Sets.
After reviewing data from a sample, an inference can be made about the population. For example,
Find a data set on the internet. Some suggested search terms: Free Data Sets, Medical Data Sets, Education Data Sets.
In: Math
You may need to use the appropriate appendix table or technology to answer this question.
A simple random sample of 60 items from a population with σ = 6 resulted in a sample mean of 38. (Round your answers to two decimal places.)
(a)
Provide a 90% confidence interval for the population mean.
______ to ________
(b)
Provide a 95% confidence interval for the population mean.
_________ to ________
(c)
Provide a 99% confidence interval for the population mean.
_______ to _______
In: Math
I can not get my Group Statistics or Indepependent Sample test to print...keep saying one group info is missing but it shows on other reports. How is the information entered on the SPSS grid. I want to see if I am enterring something wrong or it may be the software I just purchased 2 days ago. For Problem set 1 and 2 The independent-samples t-test. show each entry for both 1 and 2. Thanks
In: Math
A homeowner is travelling overseas long-term and wants to rent out his house. A local management company advises the home-owner that average rental income for houses like his in this area, i.e. 3 bedroom semi-detached town house, is no more than 770 euro. The homeowner thinks that it is more than this. He notices a report in the local paper in which a random sample of 13 rental properties of this type, in this area, gave an average of 871.51 euro with a standard deviation of 82.74 euro. Is this evidence that the average rental income of houses of this type in this area is greater than 770 euro? To answer this, test the following hypotheses at significance level α = 0.05 H 0: μ = 770 H a: μ > 770.
Fill in the blanks in the following:
An estimate of the population mean is .
The standard error is .
The distribution is (examples: normal / t12 / chisquare4 / F5,6).
The test statistic has value TS= .
Testing at significance level α = 0.05, the rejection region is: (less/greater) than (2 dec places).
Since the test statistic (is in/is not in) the rejection region, there (is evidence/is no evidence) to reject the null hypothesis, H 0.
There (is sufficient/is insufficient) evidence to suggest that average rental income for houses like his in this area, i.e. 3 bedroom semi-detached town house, μ, is greater than 770 euro.
Were any assumptions required in order for this inference to be valid?
a: No - the Central Limit Theorem applies, which states the sampling distribution is normal for any population distribution.
b: Yes - the population distribution must be normally distributed. Insert your choice (a or b):
In: Math
Reminder: You obtain a positive test result for HIV. There is no
reason to believe that you should have a higher prior probability
of being HIV positive than the average the average person in
Australia. In Australia, about 30,000 people out of 24 million
people are HIV positive. The test has a false negative rate of 0.2%
(i.e., the probability of obtaining a negative result for a person
who is HIV positive is 0.002) and a false positive rate of 2.5%
(i.e., the probability of obtaining a positive result for a person
who is HIV negative is 0.025). After obtaining this test result,
what are the posterior odds in favour of you being HIV
positive?
A. 0.001 (this corresponds to odds of about 1 to 911 that you are
HIV positive)
B. 0.015 (this corresponds to odds of about 1 to 67 that you are
HIV positive)
C. 0.063 (this corresponds to odds of about 1 to 16 that you are
HIV positive)
D. 0.072 (this corresponds to odds of about 1 to 14 that you are
HIV positive)
E. 0.050 (this corresponds to odds of about 1 to 20 that you are
HIV positive)
In: Math
In case studies, what do we mean by “operationalizing the variables”?
In: Math
two randomly assigned groups are compared in a health pilot evaluation project. data down on both groups are assumed to be normally distributed. the mean for the group 1 is 280, with a standard deviation of 15. the mean for group 2 is 230, with a standard deviation of 8. the number of observation for each group is 45. assume the level of significance is 5%. determine whether these two groups are statistically similar. show your hypothesis, calculated and critical t-values, decision and conclusion.
In: Math
In: Math