In: Math
The president of Amalgamated Retailers International, Sam Peterson, has asked for your assistance in studying the market penetration for the company’s new cell phone. You are asked to determine if the market share is equal to the company’s claim of 35%. You obtain a random sample of potential customers from the area. The sample indicates that 258 out of a total sample of 800 indicate they will purchase from Amalgamated
[a] Using a probability of error , test the hypothesis that the market share equals the company’s claim of 35% versus the hypothesis that the market share is not equal to the company’s claim.
[b] Using a probability of error , test the hypothesis that the market share equals the company’s claim of 35% versus the hypothesis that the market share is less than the company’s claim.
Please Include:
n = 800
x = 258
p̄ = x/n = 0.3225
significance level, α = 0.05
Assumption:
a) Null and Alternative hypothesis:
Ho : p = 0.35
H1 : p ≠ 0.35
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.3225 - 0.35)/√(0.35 * 0.65/800) = -1.6307
Critical value :
Two tailed critical value, z crit = ABS(NORM.S.INV(0.05/2)) = 1.960
Reject Ho if z < -1.96 or if z > 1.96
p-value :
p-value = 2*(1-NORM.S.DIST(ABS(-1.6307), 1)) = 0.1029
Decision:
p-value > α, Do not reject the null hypothesis
Conclusion:
There is not enough evidence to conclude that the market share is not equal to the company’s claim.
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b)
Null and Alternative hypothesis:
Ho : p = 0.35
H1 : p < 0.35
Test statistic:
z = (p̄ -p)/√(p*(1-p)/n) = (0.3225 - 0.35)/√(0.35 * 0.65/800) = -1.6307
Critical value :
Left tailed critical value, z crit = NORM.S.INV(0.05) = -1.645
Reject Ho if z < -1.645
p-value :
p-value = NORM.S.DIST(-1.6307, 1) = 0.0515
Decision:
p-value > α, Do not reject the null hypothesis
Conclusion:
There is not enough evidence to conclude that that the market share is less than the company’s claim.