Question

Approximately 240 mL/min of CO2 is exhaled by an average adult at rest. Assuming a temperature of 37.0 degrees Celcius and 1.00 atm pressure:

A) How many moles of CO2 is this?

B) How many grams of CO2 is this?

**Please show full work so I can follow the solution for further understanding**

Answer 1

The solution for this question calls for calculations in following steps,

A. (i) Convert the given volume of CO2 at 30^o C and 1 atm pressure to its volume at NTP

( ie. at 273 K and 1 atm. pressure ) , using relation P1 V1 / T1 = P2 V2 / T2

Thus , substituting the given values -

P1 = P2 = 1atm. , T1 = ( 273 + 37 ) = 290 K , V1 = 240 ml , V2 = ? , T2 = 273

( 1 x 240 ) / 290 = ( 1 x V2 ) / 273

.......................V2 = ( 240 x 273 ) / 290

............................. = 225.93 ml.

(ii) Since , 22,400 ml of any gas at NTP is equal to one mole......

{ as per Avagadr'os law ( volume amount relationship ) }

...........so 22400 ml of CO2 at NTP = 1 mole

............& 225.93ml--------------------- = 225.93 / 22, 400

.......................................................... = 0.01 moles

B.

Since Number of moles = Weight in grams/ gram molecular mass

...............weight of CO2 = 0.01 x 44

....................................... = 0.44gms