The protein encoded by CDC33 has a molecular weight of 24 kD. There are about 6...

The protein encoded by CDC33 has a molecular weight of 24 kD. There are about 6 picograms of TOTAL protein per haploid yeast cell. The Cdc33 protein is present in 3000 copies per cell. What fraction of the total protein in a yeast cell is Cdc33 protein?

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Expert Solution

mass of the CDC33 protein= 24 kD

1 kDa=10^3 Da

so 24 kDa= 2410^3 Da

1Da= 1.66053 10^-24 g

so the mass of 3000 copies of CDC33 protein= 30002410^3 1.66053 10^-24= 1.1210^-16 g

1 g= 10^12 pg

so 1.1210^-16 g= 1.1210^-16 10^12=1.1210^-4 pg

mass of total protein in the yeast cell = 6 pg

fraction of CDC33 protein out of the total protein in a yeast cell = total mass of CDC33/total mass of protein=1.1210^-4 pg/6pg= 210^-5

gladiator answered 3 months ago

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