A certain purified protein has a molecular mass expressed as x kD (1 D = 1/12...

A certain purified protein has a molecular mass expressed as x kD (1 D = 1/12 x mass of 12C atom). Show that an aqueous solution of this protein expressed as x mg/mL is equivalent to a protein concentration of 1mM

Expert Solution

1 mL has x mg

V = 1 mL = 1*10^-3 L
mass = x mg = x*10^-3 g
molar mass = x KD = x*10^3*(1/12)*12 g = x*10^3 g
number of moles = mass / molar mass
=x*10^-3 / (x*10^3)
= 10^-6 mol

Concentration = number of moles / volume
                               = 10^-6 mol / 10^-3 L
                               =10^-3 mol/L
                              = 10^-3 M
                               = 1 mM

Proved

queen_honey_blossom answered 2 years ago

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