In: Chemistry
The answer is: \(\underline{2.8 \times 10^{4}}\) years ago. See solution below:
Decay constant \(\mathrm{k}=\ln (2) /\) half life
\(=0.000120968\) year \(^{-1}\)
\(\ln (C / C o)=-k t\)
where \(C\) is the disintegrations per minute per gram of carbon
at time \(\mathrm{t}\), and \(\mathrm{Co}\) is the initial disintegrations per minute
per gram of carbon.
\(\ln (0.49 / 15.3)=-0.000120968 \times t\)
Time \(t=2.8 \times 10^{4}\) years