Question

Based on the relative reactivity of the halogens as oxidizing agents, predict the products of the following reaction. If no reaction will occur, leave the product boxes blank and and click on "Submit".

Cl2(g)	+	2F-(aq)		?	+	?

Use the table on the information page to predict if a reaction will occur when magnesium metal and aluminum bromide(aq) are combined. If a reaction occurs, write a balanced equation for the reaction.

?	+	?		?	+	?

Write a balanced equation for the decomposition reaction described, using the smallest possible integer coefficients.

When carbonic acid decomposes, water and carbon dioxide are formed.

	?    ?		+	?

5Cu + 2ClO3-+ 12H+   Cl2 + 5Cu2++ 6H2O

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

name of the element oxidized:			name of the element reduced:
formula of the oxidizing agent:			formula of the reducing agent:

2Fe2+ + Cd2+   2Fe3+ + Cd

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

name of the element oxidized:			name of the element reduced:
formula of the oxidizing agent:			formula of the reducing agent:

Answer 1

F2 is strong oxidicing agent. It oxisized halide ion to halogen.

Cl2 + 2F^-   ----------------> no reaction occur

Cl2 + 2F^-   ----------------> F2 + 2Cl^- this reaction cannot occur

3Mg(s) + 2AlBr3 (aq) -------------> 3MgBr2 +2 Al

cabonic acid decomposes to carbondioxide and water

H2CO3 (aq) ---------------> H2O (l) + CO2(g)

5Cu + 2ClO₃^-+ 12H+ --------------->   Cl₂ + 5Cu²⁺+ 6H₂O

Cu oxidation number increases from 0 to +2 . So it is oxidation . Cu is reducing agent.

Cl oxidation number +5 to 0 decreases. So it is readuction. ClO3^- is oxidicing agent.

name of the element oxidized: Cu              name of the element reduced: Cl

formula of the oxidizing agent: ClO3^-       formula of the reducing agent: Cu

2Fe²⁺ + Cd2+ ---------------------->    2Fe³⁺ + Cd

Fe oxidation number increases from +2 to +3 . SO it is oxidation . Fe^2+ is reducing agent.

Cd oxidation number decreases from + 2 to 0 . So it is reduction. Cd^2+ is oxidicing agent.

name of the element oxidized: Fe             name of the element reduced: Cd

formula of the oxidizing agent: Cd^2+      formula of the reducing agent: Fe^2+