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A mass attached to a spring is displaced from its equilibrium position by 5cm and released....

A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?

A mass attached to a spring is displaced from its equilibrium position by  and released. The system then oscillates in simple harmonic motion with a period of . If that same mass–spring system is displaced from equilibrium by  instead, what will its period be in this case?

A) 0.5s
B) 2s
C) 1s
D) 1.4s

Solutions

Expert Solution

time period remain same = 1 sec

because
T = 2 pi (m/k)^1/2

does not depend on displacement
depends on mass and spring constant which are same in both cases

genius_generous answered 2 years ago
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