In: Economics
3) One of your investment decisions has resulted in an
earning of SR 5,000 in year one;
and this amount will increase by 3% up to year 20.
a) Assuming an interest rate of 10% find the future worth of this
investment.
[hand calculation]
b) Use MS Excel to find the future worth. Attach your solution to
this form
a.
Future worth of geometric series = A *[(1+i)^n - (1+g)^n] / (i-g)
Future worth of investment = 5000 * [(1+0.1)^20 - (1+0.03)^20] / (0.1-0.03)
= 5000 * [(1.1)^20 - (1.03)^20] / (0.07)
= 5000 * 70.30555307
= 351527.77
b.
Using Excel
year | Cash Flow |
0 | 0.00 |
1 | 5,000.00 |
2 | 5,150.00 |
3 | 5,304.50 |
4 | 5,463.64 |
5 | 5,627.54 |
6 | 5,796.37 |
7 | 5,970.26 |
8 | 6,149.37 |
9 | 6,333.85 |
10 | 6,523.87 |
11 | 6,719.58 |
12 | 6,921.17 |
13 | 7,128.80 |
14 | 7,342.67 |
15 | 7,562.95 |
16 | 7,789.84 |
17 | 8,023.53 |
18 | 8,264.24 |
19 | 8,512.17 |
20 | 8,767.53 |
NPV | 52,252.36 |
Future Worth | 3,51,527.77 |
Showing formula in excel
year | Cash Flow |
0 | 0 |
1 | 5000 |
2 | =N9*1.03 |
3 | =N10*1.03 |
4 | =N11*1.03 |
5 | =N12*1.03 |
6 | =N13*1.03 |
7 | =N14*1.03 |
8 | =N15*1.03 |
9 | =N16*1.03 |
10 | =N17*1.03 |
11 | =N18*1.03 |
12 | =N19*1.03 |
13 | =N20*1.03 |
14 | =N21*1.03 |
15 | =N22*1.03 |
16 | =N23*1.03 |
17 | =N24*1.03 |
18 | =N25*1.03 |
19 | =N26*1.03 |
20 | =N27*1.03 |
NPV | =NPV(10%,N9:N28) |
Future Worth | =FV(10%,20,,-N29) |