In: Economics
3) One of your investment decisions has resulted in an
earning of SR 5,000 in year one;
and this amount will increase by 3% up to year 20.
a) Assuming an interest rate of 10% find the future worth of this
investment.
[hand calculation]
b) Use MS Excel to find the future worth. Attach your solution to
this form
a.
Future worth of geometric series = A *[(1+i)^n - (1+g)^n] / (i-g)
Future worth of investment = 5000 * [(1+0.1)^20 - (1+0.03)^20] / (0.1-0.03)
= 5000 * [(1.1)^20 - (1.03)^20] / (0.07)
= 5000 * 70.30555307
= 351527.77
b.
Using Excel
| year | Cash Flow | 
| 0 | 0.00 | 
| 1 | 5,000.00 | 
| 2 | 5,150.00 | 
| 3 | 5,304.50 | 
| 4 | 5,463.64 | 
| 5 | 5,627.54 | 
| 6 | 5,796.37 | 
| 7 | 5,970.26 | 
| 8 | 6,149.37 | 
| 9 | 6,333.85 | 
| 10 | 6,523.87 | 
| 11 | 6,719.58 | 
| 12 | 6,921.17 | 
| 13 | 7,128.80 | 
| 14 | 7,342.67 | 
| 15 | 7,562.95 | 
| 16 | 7,789.84 | 
| 17 | 8,023.53 | 
| 18 | 8,264.24 | 
| 19 | 8,512.17 | 
| 20 | 8,767.53 | 
| NPV | 52,252.36 | 
| Future Worth | 3,51,527.77 | 
Showing formula in excel
| year | Cash Flow | 
| 0 | 0 | 
| 1 | 5000 | 
| 2 | =N9*1.03 | 
| 3 | =N10*1.03 | 
| 4 | =N11*1.03 | 
| 5 | =N12*1.03 | 
| 6 | =N13*1.03 | 
| 7 | =N14*1.03 | 
| 8 | =N15*1.03 | 
| 9 | =N16*1.03 | 
| 10 | =N17*1.03 | 
| 11 | =N18*1.03 | 
| 12 | =N19*1.03 | 
| 13 | =N20*1.03 | 
| 14 | =N21*1.03 | 
| 15 | =N22*1.03 | 
| 16 | =N23*1.03 | 
| 17 | =N24*1.03 | 
| 18 | =N25*1.03 | 
| 19 | =N26*1.03 | 
| 20 | =N27*1.03 | 
| NPV | =NPV(10%,N9:N28) | 
| Future Worth | =FV(10%,20,,-N29) |