Question

In: Electrical Engineering

can anyone solve this for me ? x(n) ={-2,-1,1,4,2} ( arrow at 1) y(n)={-4,2,-1,0,2} ( arrow...

can anyone solve this for me ?

x(n) ={-2,-1,1,4,2} ( arrow at 1)

y(n)={-4,2,-1,0,2} ( arrow at 0)

I want the convolution and correlation of those two signals, first using tabular method and then graphically

Solutions

Expert Solution


Related Solutions

solve y' +(x+2/x)y =(e^x)/x^2 ; y(1)=0
solve y' +(x+2/x)y =(e^x)/x^2 ; y(1)=0
Solve x(y^2+U)Ux -y(x^2+U)Uy =(x^2-y^2)U, U(x,-x)=1
Solve x(y^2+U)Ux -y(x^2+U)Uy =(x^2-y^2)U, U(x,-x)=1
Solve x′=x−8y, y′=x−3y, x(0)=2, y(0)=1
Solve x′=x−8y, y′=x−3y, x(0)=2, y(0)=1
Solve (1+e^x)dy/dx+(e^x)y=3x^2+1 Solve (x^3+y^3)dx+3xy^2 dy = 0 Solve (y-cos y)dx + (xsiny+x)dy = 0 Solve (1+ln...
Solve (1+e^x)dy/dx+(e^x)y=3x^2+1 Solve (x^3+y^3)dx+3xy^2 dy = 0 Solve (y-cos y)dx + (xsiny+x)dy = 0 Solve (1+ln x +y/x)dx = (1-lnx)dy Solve (y^2+yx)dx - x^2dy =0 Solve (x^2+2y^2)dx = xydy Solve Bernoulli's Equation x dy/dx + 2y = (x^4)(e^x)(y^2) Solve Bernoulli's Equation (1+x^2) dy/dx = 2xy +(e^x)(y^2) Solve IVP (3e^(x^2))dy + (xy^2)dx=0 ; y(1) = 2 Solve IVP dy/dx -2xy = e^(x^2) ; y(0)=0 Solve IVP (x^2+y^2)dx+(2xy)dy=0; y(1)=1 6. Mixture Problem Initially 40 lb of salt is dissolved in a large...
1. solve the IVP: xy''-y/x=lnx, on (0, inifnity), y(1)=-1, y'(1)=-2 2.solve the IVP: y''-y=(e^x)/sqrtx, y(1)=e, y'(1)=0...
1. solve the IVP: xy''-y/x=lnx, on (0, inifnity), y(1)=-1, y'(1)=-2 2.solve the IVP: y''-y=(e^x)/sqrtx, y(1)=e, y'(1)=0 3. Given that y1(x)=x is a solution of xy''-xy'+y=0 on (0, inifinity, solve the IVP: xy''-xy'+y=2 on(0,infinity), y(3)=2, y'(3)=1 14. solve the IVP: X'=( 1 2 3) X, X(0)=(0 ##################0 1 4####### -3/8 ##################0 0 1 ########1/4
Solve the initial value problem. y'=(y^2)+(2xy)+(x^2)-(1), y(0)=1
Solve the initial value problem. y'=(y^2)+(2xy)+(x^2)-(1), y(0)=1
Determine if exact equation, then solve: x(y+2)y' = lnx+1 , y(1) = -1
Determine if exact equation, then solve: x(y+2)y' = lnx+1 , y(1) = -1
Solve the following recurrence relation for the given initial conditions. y(n+2) - 0.3y(n + 1) + 0.02y(n) = 10 y(0) = 2; y(1) = 0
Solve the following recurrence relation for the given initial conditions.y(n+2) - 0.3y(n + 1) + 0.02y(n) = 10        y(0) = 2;    y(1) = 0
11. Solve numerically the following Boundary Value Problem. X2Y” – X(X+2)Y’ + (X+2)Y = 0 Y(1)...
11. Solve numerically the following Boundary Value Problem. X2Y” – X(X+2)Y’ + (X+2)Y = 0 Y(1) = e and Y(2) = 2e2 The value of e = 2.71828
Solve STEP BY STEP using power series about x = -1, 4(x+1)^2 y'' - 2(x+1)(x+3) y'...
Solve STEP BY STEP using power series about x = -1, 4(x+1)^2 y'' - 2(x+1)(x+3) y' + (x+4) y = 0. note, solve by power series, variable transformation by letting: w= x+1 = 0
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT