In: Physics
. A 0.56-kg ball is thrown vertically upward with an initial speed of 15.5 m/s. What is the speed of the ball when it has travelled one-half of the distance to its maximum height?
Gravitational acceleration = g = 9.81 m/s2
Mass of the ball = m = 0.56 kg
Initial speed of the ball = V1 = 15.5 m/s
Maximum height reached by the ball = H
By conservation of energy the initial kinetic energy is converted into the potential energy at maximum height.
Speed of the ball when it has traveled one-half of the distance to the maximum height = V2
Height of the ball at this instant = H1 = H/2
By conservation of energy the initial kinetic energy is converted into the potential energy plus the kinetic energy at this height.
V2 = 10.96 m/s
Speed of the ball when it has traveled one-half of the distance to the maximum height = 10.96 m/s