Question

. A 0.56-kg ball is thrown vertically upward with an initial speed of 15.5 m/s. What is the speed of the ball when it has travelled one-half of the distance to its maximum height?

Answer 1

Gravitational acceleration = g = 9.81 m/s²

Mass of the ball = m = 0.56 kg

Initial speed of the ball = V₁ = 15.5 m/s

Maximum height reached by the ball = H

By conservation of energy the initial kinetic energy is converted into the potential energy at maximum height.

Speed of the ball when it has traveled one-half of the distance to the maximum height = V₂

Height of the ball at this instant = H₁ = H/2

By conservation of energy the initial kinetic energy is converted into the potential energy plus the kinetic energy at this height.

V₂ = 10.96 m/s

Speed of the ball when it has traveled one-half of the distance to the maximum height = 10.96 m/s