A stone is thrown vertically upward at a speed of 48.00 m/s at time t=0. A...

A stone is thrown vertically upward at a speed of 48.00 m/s at time t=0. A second stone is thrown upward with the same speed 4.050 seconds later. At what time are the two stones at the same height?

Set up an equation of motion for each stone. Write the time for the second stone in terms of the time for the first stone. Solve the two equations for the unknown time.

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Expert Solution

(1)

(2)

(3)

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genius_generous answered 1 year ago

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