In: Math
Consider the following hypotheses:
H0: μ = 3,900
HA: μ ≠ 3,900
The population is normally distributed with a population standard
deviation of 510. Compute the value of the test statistic and the
resulting p-value for each of the following sample
results. For each sample, determine if you can "reject/do not
reject" the null hypothesis at the 10% significance level.
(You may find it useful to reference the appropriate
table: z table or t
table) (Negative values should be
indicated by a minus sign. Round intermediate calculations to at
least 4 decimal places. Round "test statistic" values to 2 decimal
places and "p-value" to 4 decimal
places.)
Test statistic | p-value | |||
a. | x−x− = 3,960; n = 100 | (Click to select) Reject H0 Do not reject H0 | ||
b. | x−x− = 3,960; n = 260 | (Click to select) Reject H0 Do not reject H0 | ||
c. | x−x− = 3,730; n = 33 | (Click to select) Reject H0 Do not reject H0 | ||
d. | x−x− = 3,820; n = 33 | (Click to select) Reject H0 Do not reject H0 | ||
The statistic software output for this problem is:
(a)
Test statistics = 1.18
P-value = 0.2394
Do not reject H0
b)
Test statistics = 1.90
P-value = 0.0578
Reject H0
c)
Test statistics = -1.94
P-value = 0.0555
Reject H0
d)
Test statistics = -0.90
P-value = 0.3675
Do not reject H0