A toboggan with two people on it weighs 300 lb. It starts from rest down a...

A toboggan with two people on it weighs 300 lb. It starts from rest down a slope, 1/4 mile long, from a height 200 ft above horizontal level. The coefficient of sliding friction is 3/100 and the force of the wind resistance is proportional to the square of the velocity. When the velocity is 30 ft/sec, this force is 6 lb.

(a) Find the velocity of the toboggan as a function of the distance and of the time.

(b) With what velocity will the toboggan reach the bottom of the slide?

(c) When will it reach the bottom?

(d) What would its terminal velocity be if the slide were infinite in length?

Answers:

(a) v= 74.1 (e^(0,105t)-1)/(e^(0.105t)+1), v^2=5484(1-e^(-0.0014s)

(b) 68 ft/sec

(c) 30 sec, approx.

(d) 74.1 ft/sec

I'm having trouble solving for v originally. Any help would be much appreciated.

Expert Solution

I have a strong inclination that there cannot be an exponential function in the velocity function. It is possible only when force due to air resistance is directly proportional to velocity and not its square. I have solved the problem accordingly, Please check !!

Colby Messinger answered 2 years ago

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