A hydrogen atom emits a photon when its electron falls from its 3rd excited state (?=4)...

A hydrogen atom emits a photon when its electron falls from its 3rd excited state (?=4) to its first excited state (?=2). Another electron in a box with sides of infinite potential absorbs the photon and jumps from the ground state (?=1) to the 5th excited state (?=6).

a. [2] What is the wavelength of the emitted photon? (Calculate this, don’t just look it up)

b. [3] What is the length of the box?

c. [3] Using the fact that ∫sin2(??)??=(?²−sin(2??)4?), find the probability that we will find the electron in the first quarter of the box. How does this compare to the probability of finding the electron in that quarter of the box before the absorption of the photon (when we still had ?=1)? How do these compare to the classic probability of finding the electron in that quarter of the box?

Expert Solution

genius_generous answered 2 years ago

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