In: Statistics and Probability
A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 7 years, and standard
deviation of 1.6 years.
If you randomly purchase one item, what is the probability it will
last longer than 11 years?
Solution:
Given: a manufacturer knows that their items have a normally distributed lifespan with mean = 7 years and a standard deviation = 1.6 years.
That is: X follows Normal distribution ( )
We have to find:
P( an item will last longer than 11 years ) =..........?
That is:
P( X > 11) =.........?
Thus find z score for x = 11
Thus we get:
P(X > 11 ) = P( Z > 2.50)
P(X > 11 ) = 1 - P( Z < 2.50)
( We do 1 - P( Z< 2.50) Since table gives only P( Z< z values) )
Now to get: P( Z < 2.50) look in z table for z = 2.5 and 0.00 and find corresponding area.
Thus we get: P( Z < 2.50) = 0.9938
P(X > 11 ) = 1 - P( Z < 2.50)
P(X > 11 ) = 1 - 0.9938
P(X > 11 ) = 0.0062
Thus the probability that an item will last longer than 11 years is 0.0062