In: Statistics and Probability
A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 10.3 years, and standard
deviation of 2.4 years.
If you randomly purchase 21 items, what is the probability that
their mean life will be longer than 11 years? (Give answer to 4
decimal places.)
Solution :
Given that,
mean = = 10.3
standard deviation = = 2.4
n = 21
= 10.3
= / n = 2.4 21 = 0.5237
P ( > 11 )
= 1 - P ( < 11 )
= 1 - P ( - / ) < ( 11- 10.3 / 0.5237)
= 1 - P ( z < 0.7/ 0.5237 )
= 1 - P ( z < 1.34)
Using z table
= 1 - 0.9099
= 0.0901
Probability = 0.0901